Unit 2 End of Unit Review Algebra 2 IM

Select the expression that is equivalent to  $\frac{2x^2-9x+13}{x+2}$  for x $\ne$  -2

•  $2x-1+\frac{12}{x+2}$  

•  $2x-13+\frac{39}{x+2}$  

•  $2x-17-\frac{21}{x+2}$  

•  $2x-1+\frac{14}{x+2}$  

Tags

CCSS.HSA.APR.D.6

• $3\left(1+4+4^2+.....+4^{14}\right)$

• $\frac{1-4^{15}}{1-4}$

• $\left(1-4\right)\left(1+4+4^2+...+4^{14}\right)$

• $3\frac{1-4^{15}}{1-4}$

• $3\left(1-4\right)\left(1+4+4^2+...+4^{14}\right)$

Tags

CCSS.HSA.SSE.B.4

Which figure below is a graph of $f\left(x\right)=3+\frac{2}{x-1}$ 

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Tags

CCSS.HSF-IF.C.7D

 $\frac{-15}{x-3}=\frac{x-4}{x}$  Find all values for x that make the equation true

• x = -2 and x = -6

• x = 2 and x = 6

• x = 3 and x = 4

• no solution

Tags

CCSS.HSA.REI.A.2

• Yes, since when you plug in the values for x, you get the left side and the right side of the equation to be equivalent, this means the equation is an identity.

• Yes, since when you distribute the x and the -1 on the left side of the equation you get equivalent expressions, this means the equation is an identity.

• No, since when you distribute the x and the -1 on the left side of the equation you get two equations that are not equivalent, there the equation is not an identity.

• What's an identity?

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

What does T(5) mean in this situation?

• The time it takes to go 100 miles against a 5 mph current

• The time is takes to go 5 miles against a 100 mph current

• It takes 5 hours to go the 100 miles against a 5 mph current.

• A boat rides sounds nice

Tags

CCSS.HSF.LE.B.5

At what value of c does the graph has a vertical asymptote? Explain how you know what this asymptote means in this situation?

• 12, if the current is going the same speed as the boat, the boat will not move

• 12, it means if speed of boat is 12 the current doesn't matter

• 100, it means the boat is going too fast

• No vertical asymptote, division by zero is fun, all the cool kids are doing it

Tags

CCSS.HSF-IF.C.7D

There are many square prisms with volume 200  $in^3$  . Let w represent the side length of the square base and h represent the height in inches. The the formula V, in cubic inches, of these prisms is  $V=w^2h$  and the equation for the surface area S, in square inches, is  $S=2w^2+4wh$  
Write an equation for S as a function of w when the volume of the prism is 200  $in^3$  

•  $S=2w^2+\frac{800}{w}$  

•  $S=2w^2+4w\left(\frac{200}{w^2}\right)$  

•  $S=2w^2+\frac{800w}{w^2}$  

•  $S=200\ +w^2$