Solve Quadratics (3 Methods)

Solve by Square Root (Undo)

• ±81

• ±9

• ±3

• No real solution

Tags

CCSS.HSA-REI.B.4B

Solve by Factoring

• -2, 4

• -8

• ±8

• No real solution

Tags

CCSS.HSA-REI.B.4B

Solve by Factoring (Remove a gcf first)

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic. (Remember zeros, roots, x-ints and solutions are all the same thing. Set the factors = 0 and Solve)

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Determine the values of

a, b, and c for

the quadratic equation:

4x² – 8x = 3

(Remeber to set = 0 First)

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

Solve by square root (undo)

4m² - 100 = 0

• m=25, -25

• m=96

• m=5, -5

• m=-96

Tags

CCSS.8.EE.A.2

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

What is this?

• This is the speed of light formula.
• This is the quadratic formula.
• This is the zero product property.
• This is scary.

Tags

CCSS.HSA-REI.B.4B

Solve by Isolation/Square Roots:  $2\left(x-3\right)^2+10=20$  

•  $x=5\pm\sqrt{3}$  

•  $x=\pm3$  

•  $x=3\pm\sqrt{10}$  

•  $x=3\pm\sqrt{5}$  

Tags

CCSS.HSA-REI.B.4B