Search Header Logo

Circunferencia

Authored by Luis Jiménez

Mathematics

10th Grade

CCSS covered

Used 1K+ times

Circunferencia
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

En la circunferencia  (x3)2+(y+5)2=16\left(x-3\right)^2+\left(y+5\right)^2=16  el centro es

 (3, 5)\left(3,\ 5\right)  

 (3, 5)\left(-3,\ 5\right)  

 (3,5)\left(3,-5\right)  

 (3,5)\left(-3,-5\right)  

Tags

CCSS.HSG.GPE.A.1

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Dada la circunferencia  (x+6)2+y2=16\left(x+6\right)^2+y^2=16  el radio es

4

8

16

256

Tags

CCSS.HSG.GPE.A.1

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La ecuación de la circunferencia de radio 3 unidades y centro  (2,1)\left(2,-1\right)  es

 (x+2)2+(y1)2=3\left(x+2\right)^2+\left(y-1\right)^2=3  

 (x+2)2+(y+1)2=3\left(x+2\right)^2+\left(y+1\right)^2=3  

 (x+2)2+(y1)2=9\left(x+2\right)^2+\left(y-1\right)^2=9  

 (x2)2+(y+1)2=9\left(x-2\right)^2+\left(y+1\right)^2=9  

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La gráfica de la circunferencia  (x+6)2+(y+5)2=4\left(x+6\right)^2+\left(y+5\right)^2=4   corresponde a

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSG.GPE.A.1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

La ecuación de la circunferencia de la gráfica es

(x8)2+(y+3)2=25\left(x-8\right)^2+\left(y+3\right)^2=25

(x+8)2+(y3)2=25\left(x+8\right)^2+\left(y-3\right)^2=25

(x8)2+(y+3)2=13\left(x-8\right)^2+\left(y+3\right)^2=13

(x+8)2+(y3)2=13\left(x+8\right)^2+\left(y-3\right)^2=13

Tags

CCSS.HSG.GPE.A.1

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La circunferencia  (x+1)2+(y4)2=12\left(x+1\right)^2+\left(y-4\right)^2=12  se traslada 4 unidades a la derecha y 2 unidades hacia abajo. La ecuación de la circunferencia resultante es

 (x+5)2+(y6)2=12\left(x+5\right)^2+\left(y-6\right)^2=12  

 (x+3)2+(y+2)2=25\left(x+3\right)^2+\left(y+2\right)^2=25  

 (x3)2+(y2)2=12\left(x-3\right)^2+\left(y-2\right)^2=12  

 (x5)2+(y+6)2=25\left(x-5\right)^2+\left(y+6\right)^2=25  

Tags

CCSS.HSG.CO.A.2

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La circunferencia  (x+6)2+(y4)2=21\left(x+6\right)^2+\left(y-4\right)^2=21  se traslada y resulta la ecuación  (x+2)2+(y+3)2=21\left(x+2\right)^2+\left(y+3\right)^2=21 
El vector por el que se trasladó la circunferencia es

 (8,1)\left(8,-1\right)  

 (8, 1)\left(-8,\ 1\right)  

 (4, 7)\left(-4,\ 7\right)  

 (4, 7)\left(4,\ -7\right)  

Tags

CCSS.HSG.CO.A.2

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?