AP Chemistry Unit 9 - Applications of Thermodynamics

This electrode in a voltaic cell loses mass 

• Anode
• Cathode

In a voltaic cell, the half cell that receives anions from the salt bridge is

• Cathode
• Anode

In a voltaic cell, the half cell that receives cations from the salt bridge is

• Cathode
• Anode

In the reactions

Sn⁺² + 2Fe⁺³ --> Sn⁺⁴ + 2Fe⁺²,

the reducing agent is

• Fe⁺³

• Sn⁺²

• Sn⁺⁴

• Fe⁺²

Tags

NGSS.HS-PS1-2

What is the equation and cell potential?

• 2Al³⁺ + 3Ni → 2Al + 3Ni²⁺ E^O = 1.89 V
• 2Al + 3Ni²⁺ → 2Al³⁺ + 3Ni E^O = 1.89 V
• 2Al³⁺ + 3Ni → 2Al + 3Ni²⁺ E^O = 1.43 V
• 2Al + 3Ni²⁺ → 2Al³⁺ + 3Ni E^O = 1.43 V

Tags

NGSS.HS-PS1-2

NGSS.HS-PS1-4

Calculate the cell potential of voltaic cell

• –1.51
• - 0.03
• +0.03
• +1.51

Tags

NGSS.HS-PS3-1

NGSS.HS-PS3-5

What is E^o for the following reaction?

• +0.85
• +0.51
• –1.53
• –1.87

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

What is cell potential?

• 0.67
• 0.93
• 1.47
• 1.73

Tags

NGSS.HS-PS3-1

AlF₆ ^3– + 3 e^– → Al + 6 F^{– 1}

A steady current of 10. amperes is passed though an aluminum-production cell for 15 minutes. Which of the following is the correct number of grams of aluminum produced?

• 1.9 g

• 27 g

• 0.84 g

• 54 g

AlF₆ ^3– + 3 e^– → Al + 6 F^{– 1}

Which of the following occurs in the reaction?

• AlF₆^3– is reduced at the cathode.

• Al is oxidized at the anode.

• Aluminum is converted from the –3 oxidation state to the 0 oxidation state.

• Aluminum is converted from the –3 oxidation state to the 0 oxidation state.

Tags

NGSS.HS-PS1-2