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19-20 Covid Review 2 (Differential Eq, Slope Flds)

Authored by Beth Pickett

Mathematics

11th Grade - University

CCSS covered

Used 2+ times

19-20 Covid Review 2 (Differential Eq, Slope Flds)
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12 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The rate of change in area of a region over time is directly proportional the the square of the area. Which of these correctly describes that?

dAdt=kA\frac{\text{d}A}{\text{d}t}=kA

A = kA2A\ =\ kA^2

dAdt = kA2\frac{\text{d}A}{\text{d}t}\ =\ kA^2

A = kAA\ =\ kA

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A population P is increasing over time t, measured in years, at a rate that is proportional to the population. Which of these could correctly model that?

 dPdt = 0.34P\frac{\text{d}P}{\text{d}t}\ =\ -0.34P  

 dPdt = 0.11P\frac{\text{d}P}{\text{d}t}\ =\ \frac{-0.11}{P}  

 dPdt = 0.032P\frac{\text{d}P}{\text{d}t}\ =\ 0.032P  

 dPdt = 0.12P\frac{\text{d}P}{\text{d}t}\ =\ \frac{0.12}{P}  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The rate of change in y with respect to x is inversely proportional to the square root of x. Which of these models that?

 dxdy = kx2\frac{\text{d}x}{\text{d}y}\ =\ \frac{k}{x^2}  

 dxdy = kx\frac{\text{d}x}{\text{d}y}\ =\ \frac{k}{\sqrt{x}}  

 dxdy = kx2\frac{\text{d}x}{\text{d}y}\ =\ kx^2  

 dxdy = kx2\frac{\text{d}x}{\text{d}y}\ =\ kx^2  

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

There are S students at a school. The rate at which the number of students who have tried a new app A is growing at a rate that is jointly proportional to the number of students who have tried the app to those who have not tried it.

dAdt = k×S×A\frac{\text{d}A}{\text{d}t}\ =\ k\times S\times A

dAdt = k×SA\frac{\text{d}A}{\text{d}t}\ =\ k\times\frac{S}{A}

dAdt = k×A\frac{\text{d}A}{\text{d}t}\ =\ k\times A

dAdt = k×A(SA)\frac{\text{d}A}{\text{d}t}\ =\ k\times A\left(S-A\right)

5.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Of the following, which is a solution to the differential equation, select all that apply:
 y6y+8y=0y''-6y'+8y=0  

 y=2sin(4x)y=2\sin\left(4x\right)  

 y=3e2xy=3e^{2x}  

 y=Ce4x, y=Ce^{4x},\   where C is a constant

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

The function  y = 4sin(2x)  3cos(4x)y\ =\ 4\sin\left(2x\right)\ -\ 3\cos\left(4x\right)  satisfies which of these differential equations?

 y + 4y = 36cos(4x)y''\ +\ 4y\ =\ 36\cos\left(4x\right)  

 y + 4y = 0y''\ +\ 4y\ =\ 0  

 y4y=36cos(4x)y''-4y=36\cos\left(4x\right)  

 y4y=0y''-4y=0  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

For what value of k, if any, will  y=ke2x+4cos(3x)y=ke^{-2x}+4\cos\left(3x\right)  be a solution to the differential equation  y + 9y = 26e2xy''\ +\ 9y\ =\ 26e^{-2x}  ?

2

13/5

26

No value of k

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