HALOALKANE

HALOALKANE

11th - 12th Grade

11 Qs

quiz-placeholder

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HALOALKANE

HALOALKANE

Assessment

Quiz

Chemistry

11th - 12th Grade

Hard

Created by

Hazmira Ab Hamid

Used 295+ times

FREE Resource

11 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Haloalkane is a polar molecule that undergoes nucleophilic substitution through SN1 and SN2. Arrange the following haloalkanes in order of increasing rate of unimolecular nucleophilic substitution reaction:

I. 2-chloro-2-methylpropane

II. 2-chlorobutane

III. 1-chlorobutane

I< II < III

I< III < II

III< I < II

III< II < I

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Compound C easily undergoes hydrolysis to form compound D, which forms 2-methylpropene when heated with concentrated sulphuric acid. Using the information above, proposed the structural formula for compound C

CH3CH2CH(Br)CH3

CH3CH2CH2CH(Br)CH3

CH3CH2(CH3)CH2Br

(CH3)2C(Br)CH3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is the rate of alkaline hydrolysis that is independent of the concentration of the hydroxide ion?

CH3CH2CH2CH2Cl

CH3CH(Br)CH3

C6H5CH2CH2I

(CH3)3CBr

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a chiral molecule?

CH2BrI

CH3CBr2Cl

(CH3)2CHCl

CH3CHBrCH2CH3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Alkenes react with hydrogen halides, HX to formed haloalkane. In the reaction;

I. the pi electrons are used to form a bond with the hydrogen atom from HX

II. the intermediate product is carbocation

III. the rate of reaction increases in the order: HF, HCl, HBr, HI

I only

I and II only

II and III only

I, II and III

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following species is/are nucleophile(s)?

I. OH

II. H2O

III. R3C

I only

I and II only

II and III only

I, II and III

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A is a secondary haloalkane with formula C5H11Br and optically active. Identify A.

CH3CH2CH2CH2CH2Br

CH3CH(Br)CH2CH2CH3

(CH3)2C(Br)CH2CH3

(CH3)2C(Br)C(CH3)2CH2CH3

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