log ⁡ 3 ( 9 − 2 x ) + log ⁡ 3 x = 2 \log_3\left(9-2x\right)+\log_3x=2 lo g 3 ( 9 − 2 x ) + lo g 3 x = 2

3 2 , 3 \frac{3}{2},\ 3 2 3 , 3

2 9 , 3 \frac{2}{9},\ 3 9 2 , 3

Resource Library

Math

Logarithms

Logarithmic Equations

Logarithmic equations

Authored by Edisa Zilic

Mathematics

10th - 11th Grade

Used 34+ times

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9 questions

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FILL IN THE BLANKS QUESTION

20 sec • 1 pt

What is the base of following logarithm: $\log\ 125$

(a)

MULTIPLE SELECT QUESTION

20 sec • 1 pt

The existence conditions for the base of $\log_{b\ }a$ is

$b>0$

$b=0$

$a\ne1$

$b\ne1$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_216=x$

$x=2$

$x=8$

$x=4$

$x=-3$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The domain of the following function is:
$f\left(x\right)=\log_3\left(2-x\right)$

$x<2$

$x>2$

$x\le2$

$x\ge-2$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\log\ \left(3x+1\right)=0$

$0$

$1$

$3$

$\frac{1}{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\log_2\log_2\log_2x=0$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\log_3\left(9-2x\right)+\log_3x=2$

$\frac{3}{2},\ 3$

$2,\ 3$

$-2,-3$

$\frac{2}{9},\ 3$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\frac{\log\left(2x-5\right)}{\log\left(x^2-8\right)}=\frac{1}{2}$

$\frac{11}{3},\ 3$

$\frac{11}{3}$

$3$

No solution

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\log\left(x-3\right)-\log\left(x-2\right)=\log\left(-9-x\right)$

No solutions

$-3+2\sqrt{6}$ and $-3-2\sqrt{6}$

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Logarithmic equations

What is the base of following logarithm: log⁡ 125\log\ 125log 125 (a)

The existence conditions for the base of log⁡b a\log_{b\ }alogb ​a is

log⁡216=x\log_216=xlog2​16=x

The domain of the following function is: f(x)=log⁡3(2−x)f\left(x\right)=\log_3\left(2-x\right)f(x)=log3​(2−x)

log⁡ (3x+1)=0\log\ \left(3x+1\right)=0log (3x+1)=0

log⁡2log⁡2log⁡2x=0\log_2\log_2\log_2x=0log2​log2​log2​x=0

log⁡3(9−2x)+log⁡3x=2\log_3\left(9-2x\right)+\log_3x=2log3​(9−2x)+log3​x=2

log⁡(2x−5)log⁡(x2−8)=12\frac{\log\left(2x-5\right)}{\log\left(x^2-8\right)}=\frac{1}{2}log(x2−8)log(2x−5)​=21​

log⁡(x−3)−log⁡(x−2)=log⁡(−9−x)\log\left(x-3\right)-\log\left(x-2\right)=\log\left(-9-x\right)log(x−3)−log(x−2)=log(−9−x)

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Discover more resources for Mathematics

What is the base of following logarithm: $\log\ 125$

(a)

The existence conditions for the base of $\log_{b\ }a$ is

$\log_216=x$

The domain of the following function is:
$f\left(x\right)=\log_3\left(2-x\right)$

$\log\ \left(3x+1\right)=0$

$\log_2\log_2\log_2x=0$

$\log_3\left(9-2x\right)+\log_3x=2$

$\frac{\log\left(2x-5\right)}{\log\left(x^2-8\right)}=\frac{1}{2}$

$\log\left(x-3\right)-\log\left(x-2\right)=\log\left(-9-x\right)$