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Latihan(5) Matematik Tingkatan 5

Authored by Hasmalinda Linda

Mathematics

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Latihan(5) Matematik Tingkatan 5
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10 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Kembangkan  4n(3m+2n)−3m(2m−n)4n\left(3m+2n\right)-3m\left(2m-n\right)  

 8n2+9mn−6m28n^2+9mn-6m^2  

 8n2+15mn−6m28n^2+15mn-6m^2  

 8n2+9mn+6m28n^2+9mn+6m^2  

 8n2+15mn+6m28n^2+15mn+6m^2  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Faktorkan 8h2−188h^2-18 

 2(4h2−9h)2\left(4h^2-9h\right)  

 2h(4h+9)2h\left(4h+9\right)  

 2(2h−3)(2h−3)2\left(2h-3\right)\left(2h-3\right)  

 2(2h+3)(2h−3)2\left(2h+3\right)\left(2h-3\right)  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Permudahkan  (x+2y)2−3xy\left(x+2y\right)^2-3xy  

 x2+xy−4y2x^2+xy-4y^2  

 x2−xy−4y2x^2-xy-4y^2  

 x2+xy+4y2x^2+xy+4y^2  

 x2−xy+4y2x^2-xy+4y^2  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Ungkapkan  hk2−4k28h÷h2k−16k12h3\frac{hk^2-4k^2}{8h}\div\frac{h^2k-16k}{12h^3}  sebagai satu pecahan tunggal dalam bentuk termudah.

 3h2k2(h+4)\frac{3h^2k}{2\left(h+4\right)}  

 3hk22(h−4)\frac{3hk^2}{2\left(h-4\right)}  

 2h2k3(h+4)\frac{2h^2k}{3\left(h+4\right)}  

 2hk23(h−4)\frac{2hk^2}{3\left(h-4\right)}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diberi  v=7+4(r−2v)v=7+4\left(r-2v\right)  , ungkapkan r dalam sebutan v

 r=7+9v4r=\frac{7+9v}{4}  

 r=7−9v4r=\frac{7-9v}{4}  

 r=7v−94r=\frac{7v-9}{4}  

 r=9v−74r=\frac{9v-7}{4}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diberi bahawa  2p+75=1−p\frac{2p+7}{5}=1-p  , cari nilai p.


 −27-\frac{2}{7}  

 −23-\frac{2}{3}  

 27\frac{2}{7}  

 23\frac{2}{3}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Ringkaskan  (9m3n12)2 ×m−3n5\left(9m^3n^{\frac{1}{2}}\right)^2\ \times m^{-3}n^5  


 81m2n681m^2n^6  

 81m9n−481m^9n^{-4}  

 81m4n−481m^4n^{-4}  

 81m3n681m^3n^6  

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