trigonometric equations with miss hayat

Solve on the Interval [0,2π)

tan(x)+1=2

• 0 and π

• 3π/4 and 7π/4

• π/4 and 5π/4

• 3π/4 and 5π/4

Tags

CCSS.HSF.TF.B.7

Solve

cos²θ = ½

on θ∈[0, 2π)

• θ = π /4, 7π /4

• θ = π /4, 3π /4

• θ = 3π /4, 5π /4

• θ = π/4, 3π/4, 5π/4, 7π/4

Tags

CCSS.HSF.TF.B.7

• No solution
• π/3 +2πn, 5π/3 +2πn
• π/6 +2πn, 11π/6 +2πn
• 2π/3 +2πn, 4π/3 +2πn

Tags

CCSS.HSF.TF.B.7

Find the solution over the interval [0, 2π)

• 0, π, π/6, 5π/6,
• 0, π/6, 7π/6
• π, 5π/6, 11π/6
• π, π/6, 5π/6, 7π/6, 11π/6

Tags

CCSS.HSF.TF.B.7

Which of these is NOT
 a solution to
tan θ = 0 ?

• θ = 0
• θ = π /2
• θ = π
• θ = 2π

Tags

CCSS.HSF.TF.B.7

Find the general solution of the equation.

• π/6; 11π/6

• π/6

• 11π/6

• π/3; 11π/3

Tags

CCSS.HSF.TF.B.7

Choose a good way to start solving this equation

tanx sin²x = 2 tanx

• divide tanx from both sides

• factor out tanx

• subtract 2 tanx from the left and then factor tanx out

• cancel sin²x out

Tags

CCSS.HSF.TF.B.7

csc²x = 2 is equivalent to sin²x = ½

• True

• False

Tags

CCSS.HSF.TF.C.8

Factor: sec²x − secx − 2

• (sec x)(secx − 2)

• (secx − 2)(secx − 1)

• (secx − 2)(secx + 1)

• (secx + 2)(secx − 1)

Tags

CCSS.HSA.APR.C.4

 $Solve\ for\ x:\ \ 4\sin\left(3x\right)=2,\ 0\le x\le2\pi$  

•  $\frac{\pi}{18},\frac{5\pi}{18},\frac{13\pi}{18},\frac{17\pi}{18},\frac{25\pi}{18},\frac{29\pi}{18}$  

•  $\frac{\pi}{18},\frac{5\pi}{18},\frac{25\pi}{18},\frac{29\pi}{18}$  

•  $\frac{\pi}{12},\frac{5\pi}{12},\frac{13\pi}{12},\frac{17\pi}{12},\frac{25\pi}{12},\frac{29\pi}{12}$