REQUIZ WEEK #3: Cubic Equations and Inverses

SOLVE $x^3-64=0$  

• 64

• -64

• 4

• -4

SOLVE  $^3\sqrt{x}+5=0$  

• 5

• -5

• -125

• No Solution

SOLVE  $x^3+3x^2+2x=0$  

•  $x=1,2,3$  

•  $x=0,1,2$  

•  $x=0,-1,-2$  

•  $x=-1,-2,-3$  

 $x^3-5x^2+6x=0$ solve. Check ALL that apply.

• 0

• 1

• 2

• 3

 $x^3+2x-x-2=0$  Solve by grouping, check ALL that apply

• 0

• -1

• 1

• -2

 $12x^3+2x^2-30x-5=0$  SOLVE by GROUPING

•  $-\frac{1}{6},\ \pm\sqrt{\frac{5}{2}}$  

•  $\frac{1}{6},\pm\sqrt{\frac{5}{2}}$  

•  $-\frac{1}{6},\pm\sqrt{\frac{2}{5}}$  

•  $\frac{1}{6},\pm\sqrt{\frac{2}{5}}$  

What does it mean to find the inverse of a function?

• the x's and y's are switched
• the x's and y's are divided by 2
• the x's and y's are made negative
• the x's and y's are the same

Tags

CCSS.HSF-BF.B.4A

Find the inverse: f(x) = x³-1

• f^-1(x)= ³√x+1

• f^-1(x)= ³√x-1

• f^-1(x)= (x-1)/3

• f^-1(x)= (x+1)/3

Tags

CCSS.HSF-BF.B.4A

What is the inverse of the function?

• $f^{-1}\left(x\right)=\ \left(\frac{x-9}{3}\right)^3$

• $f^{-1}\left(x\right)=\ \left(\frac{x-3}{9}\right)^3$

• $f^{-1}\left(x\right)=^3\sqrt{\frac{x-9}{3}}$

• $f^{-1}\left(x\right)=^3\sqrt{x-9}+3$

Tags

CCSS.HSF-BF.B.4A

Find the inverse of  $f\left(x\right)=\left(x-2\right)^3+1$  

•  $f^{-1}\left(x\right)=\ ^{\ 3}\sqrt{x+2}-1$  

•  $f^{-1}\left(x\right)=\ ^{\ 3}\sqrt{x+1}-2$  

•  $f^{-1}\left(x\right)=\sqrt{x-1}+2$  

•  $f^{-1}\left(x\right)=\ ^3\sqrt{x-1}+2$  

Tags

CCSS.HSF.BF.B.4