Chapter 11 Review

Chapter 11 Review

9th - 10th Grade

26 Qs

quiz-placeholder

Similar activities

Mean &...

Mean &...

10th Grade

25 Qs

QUIZ: COMBINATIONS

QUIZ: COMBINATIONS

10th - 11th Grade

25 Qs

Compound Inequalities

Compound Inequalities

9th - 10th Grade

21 Qs

Percentages

Percentages

8th - 10th Grade

22 Qs

TVNHS MATH 10 QUIZ BEE 2022

TVNHS MATH 10 QUIZ BEE 2022

10th Grade

21 Qs

G.3 Remediation

G.3 Remediation

9th Grade - University

25 Qs

S2 EOY Assessment

S2 EOY Assessment

9th Grade

22 Qs

2019/20: Allgemeinwissen 1

2019/20: Allgemeinwissen 1

8th - 12th Grade

26 Qs

Chapter 11 Review

Chapter 11 Review

Assessment

Quiz

Mathematics

9th - 10th Grade

Practice Problem

Medium

Created by

M VT

Used 21+ times

FREE Resource

AI

Enhance your content

Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...

26 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is the volume?

36 cm3

100 cm3

216 m3

None of the above

Answer explanation

V=Bh
B is area of the base. The base is a triangle.
Area of a triangle is 12bh\frac{1}{2}bh .


The base of this triangle is 3 and the height is 4.
1234=6\frac{1}{2}\cdot3\cdot4=6 , so B = 6
What is height (h) in the volume formula? That's the height of the prism itself, which is h=6.

V=Bh
V = (6)(6)
V = 36 cm336\ cm^3

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is the volume?

141.4 in3

231.4 in3

93.6 in3

None of the above

Answer explanation

V=πr2hV=\pi r^2h
r is the radius, which is r = 3 here.
h is the height, which is h = 5 here.

V=π (3)2(5)V=\pi\ \cdot\left(3\right)^2\left(5\right)
V=π(9)(5)V=\pi\left(9\right)\left(5\right)
V=45πV=45\pi
V=141.3716694V=141.3716694

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

What is the volume?

21 mm3

42 mm3

17 mm3

None of the above

Answer explanation

V=13BhV=\frac{1}{3}Bh
B is the area off the base. This pyramid has a square base. What is the area of a square with sides 3mm long? 32=93^2=9
The area is 9, so B = 9.
h is the height of the pyramid itself, which is given as h = 7.

V=13(9)(7)V=\frac{1}{3}\left(9\right)\left(7\right)
V=21V=21

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the prism.

94

23

105

None of the above

Answer explanation

S.A.=ph+2BS.A.=ph+2B
The base here is rectangular.
The area of a rectangle is l*w.
The length of the base is 3 and the width is 5.
So the area of the base is 3*5, or B = 15.
p is the perimeter of the base (sum of all the side lengths). If the base has 2 sides that measure 3 and 2 sides that measure 5, then p = 3+3+5+5, which is p=16.
The height of the prism is h = 4.

S.A. =(16)(4)+2(15)S.A.\ =\left(16\right)\left(4\right)+2\left(15\right)

S.A.=64+30S.A.=64+30
S.A. = 94S.A.\ =\ 94

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the cylinder in terms of pi.

54π54\pi

35π35\pi

62π62\pi

None of the above

Answer explanation

S.A.=2πrh + 2πr2S.A.=2\pi rh\ +\ 2\pi r^2
We are given 6, which is the DIAMETER.
62=3\frac{6}{2}=3 , so 3 is the radius, r. r = 3.

The height (h) of the entire cylinder is 6.

S.A.=2π(3)(6)+2π(3)2S.A.=2\pi\left(3\right)\left(6\right)+2\pi\left(3\right)^2
S.A.=2π(18)+ 2π(9)S.A.=2\pi\left(18\right)+\ 2\pi\left(9\right)
S.A. = 36π+18πS.A.\ =\ 36\pi+18\pi
S.A. = 54πS.A.\ =\ 54\pi

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the lateral area of the cone in terms of pi.

60π60\pi

35π35\pi

80π80\pi

None of the above

Answer explanation

L.A.=πrlL.A.=\pi rl
'r' is the radius, 6, so r = 6.
'l' is the slant height. We are given both the height and the slant height, but we just need 10, which is our slant height, so l = 10.

L.A.=π(6)(10)L.A.=\pi\left(6\right)\left(10\right)
L.A.=60πL.A.=60\pi

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the cone in terms of pi.

144π144\pi

152π152\pi

128π128\pi

None of the above

Answer explanation

S.A.=πrl + πr2S.A.=\pi rl\ +\ \pi r^2
r is the radius, which is given, so r = 8.
'l' is the slant height, which is given, so l = 10.
S.A.=π(8)(10)+π(8)2S.A.=\pi\left(8\right)\left(10\right)+\pi\left(8\right)^2
S.A. = 80π+64πS.A.\ =\ 80\pi+64\pi
S.A.=144πS.A.=144\pi

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?