Writing the Standard Equation of a circle

Writing the Standard Equation of a circle

10th Grade

10 Qs

quiz-placeholder

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Writing the Standard Equation of a circle

Writing the Standard Equation of a circle

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Medium

CCSS
HSG.GPE.A.1, HSA.APR.C.4, 7.G.B.5

Standards-aligned

Created by

Diana Banzet

Used 83+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Write the equation of a circle with a center  (0,0) \left(0,0\right)\   and a radius of 9 

 x2 +y2=81x^{2\ }+y^2=81  

 x2 +y2=9x^{2\ }+y^2=9  

 x2 +y2 =3x^{2\ }+y^{2\ }=3  

 x2+y2=0x^2+y^2=0  

Tags

CCSS.HSG.GPE.A.1

2.

FILL IN THE BLANK QUESTION

30 sec • 1 pt

Find the center of a circle with an equation of  x22x+1+y2+6y+9=16x^2-2x+1+y^2+6y+9=16  Write the center using parenthesis

 (    ,    )

Tags

CCSS.HSG.GPE.A.1

3.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Given the equation, check the all the correct answers that correspond to the equation
 x2+4x+4+y2+2y+2 =36x^2+4x+4+y^2+2y+2\ =36  

radius = 6 

radius = 36 

standard form of equation:  (x+2)2 +(y+1)2=36\left(x+2\right)^{2\ }+\left(y+1\right)^2=36  

standard form of equation:  (x+4)2+(y+2)2=36\left(x+4\right)^2+\left(y+2\right)^2=36  

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Given the equation, check the all the correct answers that correspond to the equation
 x26x+9+y2=4x^2-6x+9+y^2=4  

center ( 0, 3);  r = 4

center ( 3, 0);  r = 2

standard form of equation:  (x3)2 +y2=4\left(x-3\right)^{2\ }+y^2=4  

standard form of equation:  (x9)2+y2=4\left(x-9\right)^2+y^2=4  

standard form of equation:  x2+(y3)2=2x^2+\left(y-3\right)^2=2  

Tags

CCSS.HSG.GPE.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the center and radius given the equation
 (x5)2+(y+1)2=25\left(x-5\right)^2+\left(y+1\right)^2=25  

center: (5, 1)  r = 5

center: (-5, -1)  r = 5

center: (-5, 1)  r = 5

center: (5, -1)  r = 5

Tags

CCSS.HSG.GPE.A.1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the center and radius given the equation
 (x3)2+(y5)2=49\left(x-3\right)^2+\left(y-5\right)^2=49  

center: (3, 5)  r = 7

center: (3, 5)  r = 49

center: (-3, -5)  r = 7

center: (-3, 5)  r = 49

Tags

CCSS.HSG.GPE.A.1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Factor the perfect square trinomial
 x2+10x+25x^2+10x+25  

 (x+10)2\left(x+10\right)^2  

 (x+5)2\left(x+5\right)^2  

 (x10)2\left(x-10\right)^2  

 (x5)2\left(x-5\right)^2  

Tags

CCSS.HSA.APR.C.4

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