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Derivacije ispit

Authored by Iva Pribeg

Mathematics

12th Grade

Used 2+ times

Derivacije ispit
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7 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Derivacija funkcije  f(x)=34x4x3+2x+1000f\left(x\right)=\frac{3}{4}x^4-x^3+2x+1000  jednaka je

 3x33x2+23x^3-3x^2+2  

 12x33x2+2x+100012x^3-3x^2+2x+1000  

 x43x+2x^{4^{ }}-3x+2  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Derivacija funkcije  f(x)=sinx(x32x+1)f\left(x\right)=\sin x\cdot\left(x^3-2x+1\right)  jednaka je

 cosx(x32x+1)+sinx(3x22)\cos x\cdot\left(x^3-2x+1\right)+\sin x\cdot\left(3x^2-2\right)  

 sinx(x32x+1)cosx(3x22)\sin x\cdot\left(x^3-2x+1\right)-\cos x\cdot\left(3x^2-2\right)  

 cosx(x32x+1)sinx(3x22)\cos x\cdot\left(x^3-2x+1\right)-\sin x\cdot\left(3x^2-2\right)  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Derivacija funkcije  f(x)=x2+3cosxf\left(x\right)=\frac{x^2+3}{\cos x}  jednaka je

 2xcosx+(x2+3)sinxcos2x\frac{2x\cdot\cos x+\left(x^2+3\right)\cdot\sin x}{\cos^2x}  

 2xcosx(x2+3)sinxcos2x\frac{2x\cdot\cos x-\left(x^2+3\right)\cdot\sin x}{\cos^2x}  

 2xcosx+(x2+3)sinxcosx\frac{2x\cdot\cos x+\left(x^2+3\right)\sin x}{\cos x}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Derivacija funkcije  f(x)=3sin3(3x+5)f\left(x\right)=3\sin^3\left(3x+5\right)  jednaka je

 27sin2(3x+5)cos(3x+5)27\sin^2\left(3x+5\right)\cdot\cos\left(3x+5\right)  

 9sin2(3x+5)cos(3x+5)9\sin^2\left(3x+5\right)\cos\left(3x+5\right)  

 27sin23xcos3x27\sin^23x\cdot\cos3x  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jednadžba tangente na krivulju  y=x240y=\sqrt{x^2-40}  u točki s apscisom 7 glasi:

 y=73x+403y=\frac{7}{3}x+\frac{40}{3}  

 y=73x403y=\frac{7}{3}x-\frac{40}{3}  

 y=73x403y=-\frac{7}{3}x-\frac{40}{3}  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Koja je druga derivacija funkcije  f(x)=sin(2x)f\left(x\right)=\sin\left(2x\right) ?

 f(x)=4cos(2x)f'\left(x\right)=-4\cos\left(2x\right)  

 f(x)=4sin(2x)f'\left(x\right)=-4\sin\left(2x\right)  

 f(x)=4sin(2x)f'\left(x\right)=4\sin\left(2x\right)  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Odredi derivaciju funkcije  f(x)=e2xf\left(x\right)=e^{2x} .

 f(x)=2exf'\left(x\right)=2e^x  

 f(x)=e2xf'\left(x\right)=e^{2x}  

 f(x)=2e2xf'\left(x\right)=2e^{2x}  

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