T&T6: Ex2.3 Solving Linear and Quadratic Equations

Which of the following represents the first step in solving:

y = x² + 3x - 5

y = x + 3

• x² - 3x + 5 = x - 3

• x² + 3x - 5 = x + 3

• x² + 3x - 5 + x + 3 = 0

• x² + 3x - 5 = 0

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Find the solution:
y = x² - 4x + 6
y = x + 2

• (3, 1) and (6, 4)
• (-1, 1) and (4, 2)
• (1, 3) and (4, 6)
• (1, 4) and (3, 6)

Tags

CCSS.HSA.REI.C.7

Determine the solution to the given linear-quadratic function.

• (0, 0)
• (3, 0)
• (2, -3)
• (-3, 2)

Tags

CCSS.HSA.REI.C.7

Two equations were graphed on the set of axes below.  Which point is a solution to the system of equations ?

• (0,3)
• (5,0)
• (2,-3)
• (8,9)

Tags

CCSS.HSA.REI.C.7

Solve the system of linear and quadratic equations using substitution:
y = 5
y = 2x² - 16x + 29

• (6, 5) and (2, 5)
• (2, 6)
• (6, 2)
• (5, 6) and (5, 2)

Tags

CCSS.HSA.REI.C.7

Determine the number of solutions to the given linear-quadratic system.

• 0 solutions
• 1 solution
• 2 solutions
• 3 solutions

Tags

CCSS.HSA.REI.C.7

Determine if the point (2,0) is a solution to the following system:

y=2x - 4

y=x² - 4

• Yes, because it works in one equation.

• Yes, because it works in the both equations.

• No, because it works in neither equation.

• No, because it works in only one equation.

Tags

CCSS.HSA.REI.C.7

Which of the following graphs correctly represents:

y=x²

y=-2x+1

• 
• 
• 
• 

Solve the System Graphically.

 $y=-\left(x-2\right)^2+4$ 

  $y=-5$  

• (-1,-5)

• (5,-5)

• (-1,-5) and (5,-5)

• (-5,5) 

Tags

CCSS.HSA.REI.C.7

 $y-5=\left(x-2\right)^2$  

 $x+2y=6$  

Solve the system.

• (0,0)

• No Solution

• (0,2)

• (2,0)

Tags

CCSS.HSA.REI.C.7