Base e and Natural Logarithm

Write the equation in logarithmic form.
 $e^3=x$  

Write the equation in exponential form. 
 $\ln53=x$   

Write the equation in logarithmic form.
 $e^x=36$  

 Write the equation in exponential form. 
 $\ln x=18$  

Condense the expression as a single logarithm.

 $\ln4+\ln3x$  

Condense the expression as a single logarithm.

 $\frac{1}{2}\cdot\ln256-3\cdot\ln2$  

 $\ln x$ is equivilant to what?  

Solve the equation. Round your answer to four decimal places.
 $3e^x+1=5$  
 $x=$   (a)  

Simplify e^ln(x)

Solve the following equation for x. Round your solution to two decimal places.

ln2x - ln41 = 2