STANDARD FORM to SLOPE INTERCEPT FORM

What is your first step in changing the standard form equation 4x+2y=12 to slope-intercept form?

• subtract 12 from both sides of the equation
  
  $4x+2y\ -12\ =\ 0$

• subtract 4x from both sides of the equation
  
  $2y=-4x\ +12$

• add 4x to both sides of the equation
  
  $2y\ =\ 4x+12$

• throw my computer across the room

Tags

CCSS.HSA.REI.A.1

Now that the equation is 2y = -4x+12 what is your second step?

• Multiply everything by Pi
  
  $2\pi y=-4\pi x+12\pi$

• divide everything by -4
  
  $-\frac{1}{2\ }y\ =\ x-3$

• divide everything by 2
  
  $y=-2x+6$

• subtract 12 from both sides of the equation
  
  $2y-12=-4x$

Tags

CCSS.HSA.REI.A.1

From the equation: y = -2x +6 what is the slope of the line?

• y

• 6

• x

• -2

Tags

CCSS.HSS.ID.C.7

From the equation: y = -2x+6 what is the y-intercept of the line?

• y

• 6

• x

• -2

Tags

CCSS.HSF.IF.C.7

CCSS.HSS.ID.C.7

What is the y-intercept?

• The point where the graph crosses the x-axis

• please make this stop

• The point where the graph crosses the y-axis

Tags

CCSS.HSF.IF.B.4

CCSS.HSS.ID.C.7

Solve this standard form equation so that it is in slope intercept form 6x+12y = 48

• 48= 6x+12y

• $y\ =\frac{1}{2}x\ -4$

• $y\ =\ -2x+4$

• $y\ =\ -\frac{1}{2}x+4$

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.SSE.B.3

Solve this equation in standard form so that it is in slope intercept form 4x-2y = 20

• $y=2x-10$

• $y=\ 2x+10$

• $y\ =\ -2x\ -10$

• $y\ =\ -2x+10$

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Solve the equation in standard form so that it is in y-intercept form 12x+6y=24 (do not use spaces in your answer)

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3