Write a linear equation that represents the height, h, of the plant after t days.

h = 2 t + 10 h\ =\ 2t+10 h = 2 t + 1 0

h = 10 t + 2 h=10t+2 h = 1 0 t + 2

t = 2 h + 10 t=2h+10 t = 2 h + 1 0

h = − 2 t + 10 h=-2t+10 h = − 2 t + 1 0

The points A and B have coordinates (-4, 9) and (6, 49) respectively. Hence, find the equation of the line perpendicular to AB and passing through B.

y = − 1 4 x + 101 2 y=-\frac{1}{4}x+\frac{101}{2} y = − 4 1 x + 2 1 0 1

y = 4 x + 10 y=4x+10 y = 4 x + 1 0

y = − 1 4 x + 10 y=-\frac{1}{4}x+10 y = − 4 1 x + 1 0

y = − 1 4 x − 5 y=-\frac{1}{4}x-5 y = − 4 1 x − 5

Functions f ( x ) = 2 x + 5 f\left(x\right)=2x+5 f ( x ) = 2 x + 5 and g ( x ) = 3 x + 2 x − 4 g\left(x\right)=\frac{3x+2}{x-4} g ( x ) = x − 4 3 x + 2 . Find f − 1 ( x ) f^{-1}\left(x\right) f − 1 ( x )

f − 1 ( x ) = x − 5 2 f^{-1}\left(x\right)=\frac{x-5}{2} f − 1 ( x ) = 2 x − 5

f − 1 ( x ) = x 2 f^{-1}\left(x\right)=\frac{x}{2} f − 1 ( x ) = 2 x

f − 1 ( x ) = 5 x − 2 f^{-1}\left(x\right)=\frac{5}{x-2} f − 1 ( x ) = x − 2 5

f − 1 ( x ) = x − 2 5 f^{-1}\left(x\right)=\frac{x-2}{5} f − 1 ( x ) = 5 x − 2

Functions f ( x ) = 2 x + 5 f\left(x\right)=2x+5 f ( x ) = 2 x + 5 and g ( x ) = 3 x + 2 x − 4 g\left(x\right)=\frac{3x+2}{x-4} g ( x ) = x − 4 3 x + 2 . Find g − 1 ( x ) g^{-1}\left(x\right) g − 1 ( x )

g − 1 ( x ) = 2 + 4 x x − 3 g^{-1}\left(x\right)=\frac{2+4x}{x-3} g − 1 ( x ) = x − 3 2 + 4 x

g − 1 ( x ) = 2 − 4 x x − 3 g^{-1}\left(x\right)=\frac{2-4x}{x-3} g − 1 ( x ) = x − 3 2 − 4 x

g − 1 ( x ) = 2 − 4 x x + 3 g^{-1}\left(x\right)=\frac{2-4x}{x+3} g − 1 ( x ) = x + 3 2 − 4 x

g − 1 ( x ) = 2 + 4 x x + 3 g^{-1}\left(x\right)=\frac{2+4x}{x+3} g − 1 ( x ) = x + 3 2 + 4 x

Functions f ( x ) = 2 x + 5 f\left(x\right)=2x+5 f ( x ) = 2 x + 5 and g ( x ) = 3 x + 2 x − 4 g\left(x\right)=\frac{3x+2}{x-4} g ( x ) = x − 4 3 x + 2 . Find g f f ( x ) gff\left(x\right) g f f ( x )

g f f ( x ) = 12 x + 47 4 x + 11 gff\left(x\right)=\frac{12x+47}{4x+11} g f f ( x ) = 4 x + 1 1 1 2 x + 4 7

g f f ( x ) = 12 x + 43 4 x + 11 gff\left(x\right)=\frac{12x+43}{4x+11} g f f ( x ) = 4 x + 1 1 1 2 x + 4 3

g f f ( x ) = x + 47 4 x − 11 gff\left(x\right)=\frac{x+47}{4x-11} g f f ( x ) = 4 x − 1 1 x + 4 7

g f f ( x ) = 12 x − 47 4 x − 11 gff\left(x\right)=\frac{12x-47}{4x-11} g f f ( x ) = 4 x − 1 1 1 2 x − 4 7

Functions f ( x ) = 2 x + 5 f\left(x\right)=2x+5 f ( x ) = 2 x + 5 and g ( x ) = 3 x + 2 x − 4 g\left(x\right)=\frac{3x+2}{x-4} g ( x ) = x − 4 3 x + 2 . Find g f f ( 5 ) gff\left(5\right) g f f ( 5 )

107 31 \frac{107}{31} 3 1 1 0 7

− 107 31 -\frac{107}{31} − 3 1 1 0 7

31 107 \frac{31}{107} 1 0 7 3 1

− 31 107 -\frac{31}{107} − 1 0 7 3 1

MATH115 FINAL EXAM

Authored by Danphil Daniel

Mathematics

11th Grade - University

Used 8+ times

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MULTIPLE CHOICE QUESTION

15 mins • 1 pt

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find A X B.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find $\left|C\right|$

-33

-23

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find $A^{-1}$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Hence, solve the simultaneous equation using the matrix method
$2x-y=2$
$x+2y=11$

x = 3 & y = 4

x = 2 & y = 5

x = -3 & y = 4

x = -3 & y = -4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is the initial volume of the water in the tank?

210 liters

3.5 liters

206.5 liters

0 liters

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