Bentuk rasional dari 4 2 \frac{4}{\sqrt{2}} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 4 adalah …

2 2 2\sqrt{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 \sqrt{2} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Hasil dari 4 3 × 5 2 4\sqrt{3}×5\sqrt{2} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> × 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> adalah ...

20 6 20\sqrt{6} 2 0 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 5 4\sqrt{5} 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Bentuk sederhana dari 4 x + 10 y – 10 z – 7 x + 5 y – 6 z 4x+10y–10z–7x+5y–6z 4 x + 1 0 y – 1 0 z – 7 x + 5 y – 6 z adalah ...

− 3 x + 15 y − 4 z -3x+15y-4z − 3 x + 1 5 y − 4 z

3 x + 15 y + 4 z 3x+15y+4z 3 x + 1 5 y + 4 z

Berikut ini yang merupakan contoh dari sifat distributif adalah …

4 ( 5 + 8 ) = ( 4 x 5 ) + ( 4 x 8 ) 4(5+8)=(4x5)+(4x8) 4 ( 5 + 8 ) = ( 4 x 5 ) + ( 4 x 8 )

( 16 + 8 ) + 2 = 16 + ( 8 + 2 ) (16+8)+2=16+(8+2) ( 1 6 + 8 ) + 2 = 1 6 + ( 8 + 2 )

( 20 × 11 ) × 5 = 20 × ( 11 x 5 ) (20×11)×5=20×(11x5) ( 2 0 × 1 1 ) × 5 = 2 0 × ( 1 1 x 5 )

20 × 4 = 4 × 20 20×4=4×20 2 0 × 4 = 4 × 2 0

20 + 17 = 17 + 20 20+17=17+20 2 0 + 1 7 = 1 7 + 2 0

Kalimat matematika pada penjumlahan dengan peragaan garis bilangan di atas adalah ….

( − 5 ) + ( − 2 ) = − 7 (-5)+(-2)=-7 ( − 5 ) + ( − 2 ) = − 7

0 + ( – 7 ) = – 7 0+(–7)=–7 0 + ( – 7 ) = – 7

( – 2 ) + 5 = – 7 (–2)+5=–7 ( – 2 ) + 5 = – 7

( – 2 ) + ( – 5 ) = – 7 (–2)+(–5)=–7 ( – 2 ) + ( – 5 ) = – 7

( – 2 ) + ( – 7 ) = – 7 (–2)+(–7)=–7 ( – 2 ) + ( – 7 ) = – 7

Penulisan pertidaksamaan dari 5 di antara 1 dan 9 adalah …

1 < 5 < − 9 1<5<-9 1 < 5 < − 9

Himpunan penyelesaian dari pertidaksamaan 3 x − 5 > x + 9 3x-5>x+9 3 x − 5 > x + 9 dengan x merupakan bilangan cacah adalah ...

x = { 8 , 9 , 10 , … } x=\left\{8,9,10,…\right\} x = { 8 , 9 , 1 0 , … }

x = { 7 , 8 , 9 , … } x=\left\{7,8,9,…\right\} x = { 7 , 8 , 9 , … }

x = { 0 , 1 , 2 , 3 , … } x=\left\{0,1,2,3,…\right\} x = { 0 , 1 , 2 , 3 , … }

x = { 1 , 2 , 3 , 4 … } x=\left\{1,2,3,4…\right\} x = { 1 , 2 , 3 , 4 … }

x = { − 8 , − 9 , − 10 , … } x=\left\{-8,-9,-10,…\right\} x = { − 8 , − 9 , − 1 0 , … }

Bentuk pertidaksamaan dari 4<7 dan 4>2 adalah ...

− 2 < 4 > 7 -2<4>7 − 2 < 4 > 7

− 2 > 4 < 7 -2>4<7 − 2 > 4 < 7

Pernyataan berikut yang termasuk himpunan kosong adalah …

Himpunan nama bulan dalam satu tahun yang huruf awalnya dimulai dengan huruf "C"

Himpunan bilangan ganjil yang habis dibagi 2

Himpunan nama buah yang huruf akhirnya diakhiri dengan huruf K

Diketahui nilai A = {1,2,3,4}, dan B = {2,4,6}. Nilai dari A ∩ B A∩B A ∩ B adalah ...

A ∩ B = { 2 , 4 } A∩B=\left\{2,4\right\} A ∩ B = { 2 , 4 }

A ∩ B = { 1 , 3 } A∩B=\left\{1,3\right\} A ∩ B = { 1 , 3 }

A ∩ B = { 1 , 3 , 6 } A∩B=\left\{1,3,6\right\} A ∩ B = { 1 , 3 , 6 }

A ∩ B = { 1 , 2 , 3 , 4 , 5 , 6 } A∩B=\left\{1,2,3,4,5,6\right\} A ∩ B = { 1 , 2 , 3 , 4 , 5 , 6 }

A ∩ B = { 2 , 4 , 6 } A∩B=\left\{2,4,6\right\} A ∩ B = { 2 , 4 , 6 }

Tes Kemampuan Dasar Matematika

Authored by Fithriyyah Aziezah

Mathematics

10th Grade

Used 140+ times

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MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari 4 x [2 + 3] : 10 = 4 x 5 : 10 = 20 : 10 = ...

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari 15 + 56 : 8 x 2 = 15 + 7 x 2 = 15 + 14 = ...

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari $3^7:3^2×3^5=⋯$

$3^5$

$3^8$

$3^9$

$3^{10}$

$3^{15}$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Bentuk rasional dari $\frac{4}{\sqrt{2}}$ adalah …

$\sqrt{2}$

$\sqrt{3}$

$2\sqrt{2}$

$2\sqrt{3}$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari $4\sqrt{3}×5\sqrt{2}$ adalah ...

$20\sqrt{6}$

$4\sqrt{5}$

$2\sqrt{3}$

$\sqrt{5}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Bentuk sederhana dari $4x+10y–10z–7x+5y–6z$ adalah ...

$-3x+15y-4z$

$3x+15y+4z$

$-3x-15y-16z$

$3x+15y-16z$

$-3x+15y-16z$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Hasil dari $(2x–3)(x+5)$ adalah ...

$2x^2+7x-10$

$-2x^2+7x-10$

$2x^2+7x-15$

$-2x^2+7x-15$

$2x^2+7x+8$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Pemfaktoran dari $4x^2–9y^2$ adalah ...

$(2x+3y)(2x-3y)$

$(2x+3y)(2x+3y)$

$(2x-3y)(2x-3y)$

$(x+3y)(x-3y)$

$(x+3y)(4x-3y)$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Hasil dari $2(4x-5)-5x+7$ adalah ...

$3x$

$3x-2$

$3x-3$

$8x+5$

$8x-7$

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$(8+7)+2=8+(7+2)$
Sifat yang berlaku pada penjumlahan diatas adalah …

komutatif

asosiatif

distributif

tertutup

terbuka

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Tes Kemampuan Dasar Matematika

Hasil dari 4 x [2 + 3] : 10 = 4 x 5 : 10 = 20 : 10 = ...

Hasil dari 15 + 56 : 8 x 2 = 15 + 7 x 2 = 15 + 14 = ...

Hasil dari 37:32×35=⋯3^7:3^2×3^5=⋯37:32×35=⋯

Bentuk rasional dari 42\frac{4}{\sqrt{2}}2​4​ adalah …

Hasil dari 43×524\sqrt{3}×5\sqrt{2}43​×52​ adalah ...

Bentuk sederhana dari 4x+10y–10z–7x+5y–6z4x+10y–10z–7x+5y–6z4x+10y–10z–7x+5y–6z adalah ...

Hasil dari (2x–3)(x+5)(2x–3)(x+5)(2x–3)(x+5) adalah ...

Pemfaktoran dari 4x2–9y24x^2–9y^24x2–9y2 adalah ...

Hasil dari 2(4x−5)−5x+72(4x-5)-5x+72(4x−5)−5x+7 adalah ...

(8+7)+2=8+(7+2)(8+7)+2=8+(7+2)(8+7)+2=8+(7+2) Sifat yang berlaku pada penjumlahan diatas adalah …

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Hasil dari $3^7:3^2×3^5=⋯$

Bentuk rasional dari $\frac{4}{\sqrt{2}}$ adalah …

Hasil dari $4\sqrt{3}×5\sqrt{2}$ adalah ...

Bentuk sederhana dari $4x+10y–10z–7x+5y–6z$ adalah ...

Hasil dari $(2x–3)(x+5)$ adalah ...

Pemfaktoran dari $4x^2–9y^2$ adalah ...

Hasil dari $2(4x-5)-5x+7$ adalah ...

$(8+7)+2=8+(7+2)$
Sifat yang berlaku pada penjumlahan diatas adalah …