Literal Equations and Formulas

Solve for the variable y in the equation:

y - x = 5

• y = 5 + x

• y = -5 - x

• y = -5 + x

• y = 5 - x

Tags

CCSS.6.EE.C.9

Solve for the variable y in the equation:

2x + 2y = 6

• y = - x + 3

• y = x + 3

• y = 2x +6

• y = - 2x + 6

Tags

CCSS.6.EE.C.9

Solve for the variable y in the following equation:

8x + 4y= 16

• y = -8x + 16

• y = 2x -4

• y = -2x + 4

• y = -8x + 12

Tags

CCSS.6.EE.C.9

Solve for the variable y in the following equation:

 $3y-6z+15=9x$  

•  $y=3x\ +\ 2z\ -\ 5$  

•  $y=3x\ -2z+5$  
  

•  $y=9x\ +6z\ -12$  
  

•  $y=9x-6z\ +18$  
  

Tags

CCSS.HSA.REI.B.3

Solve for the variable x, for the following equation:

 $3(2x+4y)-4=8$  

•  $x=2+4y$  
  

•  $x=2+2y$  
  

•  $x=2-4y$  
  

•  $x=2-2y$  
  

Tags

CCSS.HSA.REI.B.3

Solve for the variable R in the equation:

pV = nRT

(this is the ideal gas law formula)

• R= pV - nT

• R= p/n + V/T

• R= pV/nT

• R= (pV-n)/T

Tags

CCSS.HSA.CED.A.4

Solve for the variable m in the formula:

 $e=mc²$  
(This is Einstein's equations for mass-energy equivalence)

•  $m=ec²$  

•  $m=\frac{c²}{e}$  

•  $m=\frac{e}{c²}$  

•  $m=e-c²$  

Answer explanation

m is being multiplied by c², so we need to divide both sides of the equations by c² to give us  $m=\frac{e}{c²}$  

Tags

CCSS.HSA.CED.A.4

Solve for the variable the variable H in the formula:

 $V=LWH$  
(Formula for the volume of a prism)

•  $H=V-LW$  

•  $H=VLW$  

•  $H=\frac{LW}{V}$  

•  $H=\frac{V}{LW}$  

Answer explanation

H is being multiplied by L and W, so to isolate H, we need to perform the inverse of multiplication to L and W, which is division. This leaves the formula of:
 $H=\frac{V}{LW}$  

Tags

CCSS.7.G.B.6

Solve for the variable F in the following equation:

 $C=\frac{5}{9}\left(F-32\right)$  

(This is the formula converting temperature from Fahrenheit to Celsius.)

•  $F=\frac{9}{5}\left(C+32\right)$  

•  $F=\frac{9}{5}C+32$  

•  $F=\frac{5}{9}\left(C-32\right)$  

•  $F=\frac{5}{9}C-32$  

Answer explanation

F is being multiplied by  $\frac{5}{9}$  , so we need to multiply both sides of the equation by the reciprocal  $\frac{9}{5}$  . Then we need to add 32 to both sides of the equation, leaving us the formula.

 $F=\frac{9}{5}C+32$  

Tags

CCSS.HSA.CED.A.4

Solve for the variable  $m_2$  using the following formula:
 $F=G\frac{m_1\times m_2}{r²}$  

(This Newton's law of universal gravity formula)

•  $m_2=G\frac{m_1\times F}{r²}$  

•  $m_2=\frac{F\times r²}{G\times m_1}$  

•  $m_2=\frac{r²\left(F-G\right)}{m_1}$  

•  $m_2=\frac{Fr²-G}{m_1}$  

Answer explanation

 $m_2$  is being divided by r², so both sides needts to be multiplied by r².  $m_2$  is also being multiplied by G and  $m_1$  , so both sides of the equation needs to be divided by both G and  $m_2$  .

This will leave the equation:
 $m_2=\frac{F\times r²}{G\times m_1}$  

Tags

CCSS.HSA.CED.A.4