Midpoint Formula and Distance Formula

Find the MIDPOINT of the segment with the endpoints ( 6, 7 ) and ( 6, - 5 )

• (0, -1)

• (6, 1)

• (1, 6)

• (0, 1)

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8

Find the MIDPOINT of the segment with the endpoints ( 1, 7 ) and ( 9, 0 )

• (4, 3.5)

• (3.5, 5)

• (3.5, 4.5)

• (5, 3.5)

Tags

CCSS.6.NS.C.8

Find the MIDPOINT of the line segment with endpoints ( - 2, 0 ) & ( 9, - 1 ).

• ( 1, 3 )

• ( 3.5, - 0.5 )

• ( - 0.5, 3.5 )

• ( 6, - 0.5 )

Tags

CCSS.6.NS.C.6

Find the MIDPOINT:

• 
  

  $\left(3,-1\right)$
  

• $\left(-1,3\right)$

• $\left(3,4\right)$

• $\left(4,3\right)$

Tags

CCSS.HSG.GPE.B.6

Find the MIDPOINT of the line.

• ( 2, 1 )

• ( 1, 2 )

• ( - 2, 1 )

• ( 1, - 2 )

Tags

CCSS.6.NS.C.8

What is the DISTANCE between AB?

• 0

• undefined

• 5

• 4

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8

What is the distance between AB

• 0

• 8

• 9

• 7

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8

How is AB written in the distance formula?

• 
  $d\ =\ \sqrt{\left(5-3\right)^2\ +\ \left(0--2\right)^2}$
  

• $d\ =\ \sqrt{\left(2-5\right)^2\ +\ \left(3\ -0\right)^2}$

• $d\ =\ \sqrt{\left(5-3\right)^2\ -\ \left(0--2\right)^2}$

• $d\ =\ \sqrt{\left(4-3\right)^2\ -\ \left(2-4\right)^2}$

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8

The DISTANCE of line segment AB with endpoints A ( 2, 0 ) B ( - 2, 4 ) is written as:

• $d\ =\ \sqrt{\left(4-2\right)^2\ -\ \left(0-2\right)^2}$

• $d\ =\ \sqrt{\left(4-0\right)^2\ -\ \left(-2-2\right)^2}$

• $d\ =\ \sqrt{\left(-2\ +0\right)^2\ +\ \left(4+2\right)^2}$

• $d\ =\ \sqrt{\left(-2-2\right)^2\ +\ \left(4-0\right)^2}$

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8

Find the DISTANCE between the points ( 4, 3 ) and ( 0, 6 ).

• 3

• 4

• 5

• 7

Tags

CCSS.6.G.A.3

CCSS.6.NS.C.8