Jika f ( x ) = 4 cos ⁡ 2 x f\left(x\right)=4\cos2x f ( x ) = 4 cos 2 x maka nilai f ′ ( 60 ° ) = . . . f'\left(60\degree\right)=... f ′ ( 6 0 ° ) = . . . .

− 4 3 -4\sqrt{3} − 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 3 -2\sqrt{3} − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 3 -\sqrt{3} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 3 4\sqrt{3} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Hasil differensial dari T ( x ) = ( sin ⁡ x + 1 ) ( sin ⁡ x − 2 ) T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right) T ( x ) = ( sin x + 1 ) ( sin x − 2 )

sin ⁡ 2 x − cos ⁡ x \sin2x-\cos x sin 2 x − cos x

sin ⁡ 2 x + cos ⁡ x \sin\ 2x+\cos x sin 2 x + cos x

sin ⁡ 2 x − sin ⁡ x \sin2x-\sin x sin 2 x − sin x

cos ⁡ 2 x + cos ⁡ x \cos2x+\cos x cos 2 x + cos x

cos ⁡ 2 x − cos ⁡ x \cos2x-\cos x cos 2 x − cos x

g ( t ) = ( 2 − 3 cos ⁡ t ) 3 2 g\left(t\right)=\left(2-3\cos t\right)^{\frac{3}{2}} g ( t ) = ( 2 − 3 cos t ) 2 3 maka g'(t) = ...

9 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{9}{2}\ \sin\ t\ \sqrt{2-3\ \cos\ t} 2 9 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{3}{2\ }\sin t\ \sqrt{2-3\cos t} 2 3 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{5}{2}\ \sin\ t\ \sqrt{2-3\ \cos\ t} 2 5 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

7 2 cos ⁡ t 2 − 3 sin ⁡ t \frac{7}{2}\ \cos\ t\ \sqrt{2-3\ \sin\ t} 2 7 cos t 2 − 3 sin t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

9 2 cos ⁡ t 2 − 3 sin ⁡ t \frac{9}{2}\ \cos\ t\ \sqrt{2-3\sin t} 2 9 cos t 2 − 3 sin t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Jika p(x) = sin x . cos 2x, maka p '(x) = ... .

cos x cos (2x) - 2 sin x sin (2x)

cos x cos (2x) + 2 sin x sin (2x)

sin x sin (2x) - 2 cos x cos (2x)

cos x sin (2x) - 2 cos (2x) sin x

cos x sin x - 2 sin (2x) cos (2x)

Turunan pertama dari fungsi f(x) = 4 sec (6x 2 + π) adalah ... .

24 x sec (6x 2 + π) tan (6x 2 + π)

24 sec (6x 2 + π) tan (6x 2 + π)

24 sec (6x 2 + π) cot (6x 2 + π)

-24 sec (6x 2 + π) tan (6x 2 + π)

-24 x sec (6x 2 + π) tan (6x 2 + π)

TURUNAN TRIGONOMETRI

Quiz

•

Mathematics

•

12th Grade

•

Practice Problem

•

Medium

•

CCSS

HSF.IF.A.1, HSF.IF.A.2, HSF.TF.A.3

Standards-aligned

Adi Armstrong

Used 234+ times

FREE Resource

20 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunan pertama dari fungsi f(x) = 3 sin (4x) adalah ... .

f ' (x) = 3 cos (4x)

f ' (x) = 12 cos (4x)

f ' (x) = 3 sin (4x)

f ' (x) = 12 sin (4x)

f ' (x) = - 12 cos (4x)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunan pertama dari fungsi f(x) = 5 cos (2x - 1) adalah ... .

f '(x) = 10 sin (2x - 1)

f '(x) = - 10 sin (2x - 1)

f '(x) = 5 sin (2x - 1)

f '(x) = - 5 sin (2x - 1)

f '(x) = sin (2x - 1)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunana pertama dari fungsi $f\left(x\right)=\cos^2\left(1-3x\right)$ adalah ....

$3\cos\left(2-6x\right)$

$\cos\left(6x-2\right)$

$3\sin\left(2-6x\right)$

$\sin\left(6-2x\right)$

$\sin\left(1-3x\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diketahui $f\left(x\right)=\frac{1+\sin x}{\cos x}$ maka $f'\left(\frac{1}{6}\pi\right)=$ ....

$-\frac{1}{2}$

$\frac{1}{2}$

$\frac{3}{4}$

$2$

$-2$

Jika $f\left(x\right)=4\cos2x$ maka nilai $f'\left(60\degree\right)=...$ .

$-4\sqrt{3}$

$-2\sqrt{3}$

$-\sqrt{3}$

$2\sqrt{3}$

$4\sqrt{3}$

Jika f(x) = Sin x + Cos x + 3x
maka nilai dari $f'\left(\pi\right)=\ ...$

$turunan\ dari\ y\ =\ Sin^32x\ adalah..$

$\frac{\text{d}x}{\text{d}y}=3\ Sin^22x.Cos\ 2x$

$\frac{\text{d}x}{\text{d}y}=6\ Sin^22x.Cos\ 2x$

$\frac{\text{d}x}{\text{d}y}=3\ Sin^22x$

$\frac{\text{d}x}{\text{d}y}=6\ Sin^22x$

$\frac{\text{d}x}{\text{d}y}=Sin^22x.\ \cos\ 2x$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hasil differensial dari $T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)$

$\sin\ 2x+\cos x$

$\sin2x-\sin x$

$\sin2x-\cos x$

$\cos2x+\cos x$

$\cos2x-\cos x$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...$

$y^1=\sin\left(2x^3-x^4\right)$

$y^1=-\ \sin\left(2x^3-x^4\right)$

$y^1=\left(6x^2-4x^3\right)\ \cos\left(2x^3-x^4\right)$

$y^1=\left(6x^2-4x^3\right)\ \sin\left(2x^3-x^4\right)$

$y^1=-\left(6x^2-4x^3\right)\ \sin\left(2x^3-x^4\right)$

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TURUNAN TRIGONOMETRI

20 questions

Turunan pertama dari fungsi f(x) = 3 sin (4x) adalah ... .

Turunan pertama dari fungsi f(x) = 5 cos (2x - 1) adalah ... .

Turunana pertama dari fungsi f(x)=cos⁡2(1−3x)f\left(x\right)=\cos^2\left(1-3x\right)f(x)=cos2(1−3x) adalah ....

Diketahui f(x)=1+sin⁡xcos⁡xf\left(x\right)=\frac{1+\sin x}{\cos x}f(x)=cosx1+sinx​ maka f′(16π)=f'\left(\frac{1}{6}\pi\right)=f′(61​π)= ....

Jika f(x)=4cos⁡2xf\left(x\right)=4\cos2xf(x)=4cos2x maka nilai f′(60°)=...f'\left(60\degree\right)=...f′(60°)=... .

Jika f(x) = Sin x + Cos x + 3xmaka nilai dari f′(π)= ...f'\left(\pi\right)=\ ...f′(π)= ...

turunan dari y = Sin32x adalah..turunan\ dari\ y\ =\ Sin^32x\ adalah..turunan dari y = Sin32x adalah..

Turunan pertama dari fungsi f(x) = (3 sinx)(8 cos x) adalah ... .

Hasil differensial dari T(x)=(sin⁡x+1) (sin⁡x−2)T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)T(x)=(sinx+1) (sinx−2)

Turunan pertama dari y=cos⁡(2x3−x4) adalah...Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...Turunan pertama dari y=cos(2x3−x4) adalah...

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Popular Resources on Wayground

Discover more resources for Mathematics

Turunana pertama dari fungsi $f\left(x\right)=\cos^2\left(1-3x\right)$ adalah ....

Diketahui $f\left(x\right)=\frac{1+\sin x}{\cos x}$ maka $f'\left(\frac{1}{6}\pi\right)=$ ....

Jika $f\left(x\right)=4\cos2x$ maka nilai $f'\left(60\degree\right)=...$ .

Jika f(x) = Sin x + Cos x + 3x
maka nilai dari $f'\left(\pi\right)=\ ...$

$turunan\ dari\ y\ =\ Sin^32x\ adalah..$

Hasil differensial dari $T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)$

$Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...$