Jika f ( x ) = 4 cos ⁡ 2 x f\left(x\right)=4\cos2x f ( x ) = 4 cos 2 x maka nilai f ′ ( 60 ° ) = . . . f'\left(60\degree\right)=... f ′ ( 6 0 ° ) = . . . .

− 4 3 -4\sqrt{3} − 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 3 -2\sqrt{3} − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 3 -\sqrt{3} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

4 3 4\sqrt{3} 4 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Hasil differensial dari T ( x ) = ( sin ⁡ x + 1 ) ( sin ⁡ x − 2 ) T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right) T ( x ) = ( sin x + 1 ) ( sin x − 2 )

sin ⁡ 2 x − cos ⁡ x \sin2x-\cos x sin 2 x − cos x

sin ⁡ 2 x + cos ⁡ x \sin\ 2x+\cos x sin 2 x + cos x

sin ⁡ 2 x − sin ⁡ x \sin2x-\sin x sin 2 x − sin x

cos ⁡ 2 x + cos ⁡ x \cos2x+\cos x cos 2 x + cos x

cos ⁡ 2 x − cos ⁡ x \cos2x-\cos x cos 2 x − cos x

g ( t ) = ( 2 − 3 cos ⁡ t ) 3 2 g\left(t\right)=\left(2-3\cos t\right)^{\frac{3}{2}} g ( t ) = ( 2 − 3 cos t ) 2 3 maka g'(t) = ...

9 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{9}{2}\ \sin\ t\ \sqrt{2-3\ \cos\ t} 2 9 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{3}{2\ }\sin t\ \sqrt{2-3\cos t} 2 3 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 2 sin ⁡ t 2 − 3 cos ⁡ t \frac{5}{2}\ \sin\ t\ \sqrt{2-3\ \cos\ t} 2 5 sin t 2 − 3 cos t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

7 2 cos ⁡ t 2 − 3 sin ⁡ t \frac{7}{2}\ \cos\ t\ \sqrt{2-3\ \sin\ t} 2 7 cos t 2 − 3 sin t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

9 2 cos ⁡ t 2 − 3 sin ⁡ t \frac{9}{2}\ \cos\ t\ \sqrt{2-3\sin t} 2 9 cos t 2 − 3 sin t <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Jika p(x) = sin x . cos 2x, maka p '(x) = ... .

cos x cos (2x) - 2 sin x sin (2x)

cos x cos (2x) + 2 sin x sin (2x)

sin x sin (2x) - 2 cos x cos (2x)

cos x sin (2x) - 2 cos (2x) sin x

cos x sin x - 2 sin (2x) cos (2x)

Turunan pertama dari fungsi f(x) = 4 sec (6x 2 + π) adalah ... .

24 x sec (6x 2 + π) tan (6x 2 + π)

24 sec (6x 2 + π) tan (6x 2 + π)

24 sec (6x 2 + π) cot (6x 2 + π)

-24 sec (6x 2 + π) tan (6x 2 + π)

-24 x sec (6x 2 + π) tan (6x 2 + π)

TURUNAN TRIGONOMETRI

Authored by Adi Armstrong

Mathematics

12th Grade

CCSS covered

Used 234+ times

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

20 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunan pertama dari fungsi f(x) = 3 sin (4x) adalah ... .

f ' (x) = 3 cos (4x)

f ' (x) = 12 cos (4x)

f ' (x) = 3 sin (4x)

f ' (x) = 12 sin (4x)

f ' (x) = - 12 cos (4x)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunan pertama dari fungsi f(x) = 5 cos (2x - 1) adalah ... .

f '(x) = 10 sin (2x - 1)

f '(x) = - 10 sin (2x - 1)

f '(x) = 5 sin (2x - 1)

f '(x) = - 5 sin (2x - 1)

f '(x) = sin (2x - 1)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunana pertama dari fungsi $f\left(x\right)=\cos^2\left(1-3x\right)$ adalah ....

$3\cos\left(2-6x\right)$

$\cos\left(6x-2\right)$

$3\sin\left(2-6x\right)$

$\sin\left(6-2x\right)$

$\sin\left(1-3x\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diketahui $f\left(x\right)=\frac{1+\sin x}{\cos x}$ maka $f'\left(\frac{1}{6}\pi\right)=$ ....

$-\frac{1}{2}$

$\frac{1}{2}$

$\frac{3}{4}$

$2$

$-2$

Jika $f\left(x\right)=4\cos2x$ maka nilai $f'\left(60\degree\right)=...$ .

$-4\sqrt{3}$

$-2\sqrt{3}$

$-\sqrt{3}$

$2\sqrt{3}$

$4\sqrt{3}$

Jika f(x) = Sin x + Cos x + 3x
maka nilai dari $f'\left(\pi\right)=\ ...$

$turunan\ dari\ y\ =\ Sin^32x\ adalah..$

$\frac{\text{d}x}{\text{d}y}=3\ Sin^22x.Cos\ 2x$

$\frac{\text{d}x}{\text{d}y}=6\ Sin^22x.Cos\ 2x$

$\frac{\text{d}x}{\text{d}y}=3\ Sin^22x$

$\frac{\text{d}x}{\text{d}y}=6\ Sin^22x$

$\frac{\text{d}x}{\text{d}y}=Sin^22x.\ \cos\ 2x$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hasil differensial dari $T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)$

$\sin\ 2x+\cos x$

$\sin2x-\sin x$

$\sin2x-\cos x$

$\cos2x+\cos x$

$\cos2x-\cos x$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...$

$y^1=\sin\left(2x^3-x^4\right)$

$y^1=-\ \sin\left(2x^3-x^4\right)$

$y^1=\left(6x^2-4x^3\right)\ \cos\left(2x^3-x^4\right)$

$y^1=\left(6x^2-4x^3\right)\ \sin\left(2x^3-x^4\right)$

$y^1=-\left(6x^2-4x^3\right)\ \sin\left(2x^3-x^4\right)$

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Microsoft

or continue with

Facebook

Apple

Others

Already have an account?

Similar Resources on Wayground

20 questions

Mnożenie do 50

Quiz

•

1st - 12th Grade

15 questions

Remidial Dimensi 3

Quiz

•

12th Grade

20 questions

Kuis Kaidah Pencacahan

Quiz

•

12th Grade

20 questions

Me divierto con las Matemáticas LILEGRE 8° y 9° 2020.

Quiz

•

1st Grade - University

20 questions

Thử thách Toán Tuần 11

Quiz

•

5th Grade - University

17 questions

The Definite Integral

Quiz

•

12th Grade

20 questions

Evaluación Formativa: Medidas de Dispersión

Quiz

•

12th Grade

15 questions

PELUANG BINOMIAL

Quiz

•

10th - 12th Grade

Popular Resources on Wayground

10 questions

HCS SCI 03 Summer School Assessment 1

Quiz

•

3rd Grade

15 questions

HCS SCI 05 Summer School Assessment 1 Review

Quiz

•

5th Grade

22 questions

Day 9 Equations and Inequalities Review

Quiz

•

9th Grade

10 questions

Writing and Identifying Ratios Practice

Quiz

•

5th - 6th Grade

7 questions

PYRAMID PERSPECTIVES part 1

Presentation

•

9th - 12th Grade

12 questions

Understanding the Fourth of July

Quiz

•

9th Grade

15 questions

Soccer World Cup Quiz Questions

Quiz

•

7th Grade

Discover more resources for Mathematics

7 questions

PYRAMID PERSPECTIVES part 1

Presentation

•

9th - 12th Grade

TURUNAN TRIGONOMETRI

Turunan pertama dari fungsi f(x) = 3 sin (4x) adalah ... .

Turunan pertama dari fungsi f(x) = 5 cos (2x - 1) adalah ... .

Turunana pertama dari fungsi f(x)=cos⁡2(1−3x)f\left(x\right)=\cos^2\left(1-3x\right)f(x)=cos2(1−3x) adalah ....

Diketahui f(x)=1+sin⁡xcos⁡xf\left(x\right)=\frac{1+\sin x}{\cos x}f(x)=cosx1+sinx​ maka f′(16π)=f'\left(\frac{1}{6}\pi\right)=f′(61​π)= ....

Jika f(x)=4cos⁡2xf\left(x\right)=4\cos2xf(x)=4cos2x maka nilai f′(60°)=...f'\left(60\degree\right)=...f′(60°)=... .

Jika f(x) = Sin x + Cos x + 3xmaka nilai dari f′(π)= ...f'\left(\pi\right)=\ ...f′(π)= ...

turunan dari y = Sin32x adalah..turunan\ dari\ y\ =\ Sin^32x\ adalah..turunan dari y = Sin32x adalah..

Turunan pertama dari fungsi f(x) = (3 sinx)(8 cos x) adalah ... .

Hasil differensial dari T(x)=(sin⁡x+1) (sin⁡x−2)T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)T(x)=(sinx+1) (sinx−2)

Turunan pertama dari y=cos⁡(2x3−x4) adalah...Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...Turunan pertama dari y=cos(2x3−x4) adalah...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Turunana pertama dari fungsi $f\left(x\right)=\cos^2\left(1-3x\right)$ adalah ....

Diketahui $f\left(x\right)=\frac{1+\sin x}{\cos x}$ maka $f'\left(\frac{1}{6}\pi\right)=$ ....

Jika $f\left(x\right)=4\cos2x$ maka nilai $f'\left(60\degree\right)=...$ .

Jika f(x) = Sin x + Cos x + 3x
maka nilai dari $f'\left(\pi\right)=\ ...$

$turunan\ dari\ y\ =\ Sin^32x\ adalah..$

Hasil differensial dari $T\left(x\right)=\left(\sin x+1\right)\ \left(\sin x-2\right)$

$Turunan\ pertama\ dari\ y=\cos\left(2x^3-x^4\right)\ adalah...$