Math 1 Round 2: Test 2  Sept 19,2020

Math 1 Round 2: Test 2 Sept 19,2020

9th - 11th Grade

14 Qs

quiz-placeholder

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Math 1 Round 2: Test 2  Sept 19,2020

Math 1 Round 2: Test 2 Sept 19,2020

Assessment

Quiz

Mathematics

9th - 11th Grade

Medium

CCSS
HSF.IF.B.4, 8.F.A.3, HSA.CED.A.2

+14

Standards-aligned

Created by

Keith Hodges

Used 6+ times

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14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Write the following equation in slope-intercept form:
4x - 3y = 12

y = -4/3x + 3
y = -4x + 12
y = 4/3x - 4
y = 4/3x - 12

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Determine the slope and y-intercept.         y = 3/2x + 3

slope: 5   y-intercept:  (0,3) 
slope: 3/2   y-intercept:  (0,3) 
slope:  4  y-intercept:  (0,3/2)
slope: 1/5   y-intercept:  (0,5) 

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Which could be the graph of the equation y = 1/3x - 2?

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Which graph represents y = 3x?

Media Image
Media Image
Media Image

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the y-intercept in y=-4x-5

-4
-4x
5
-5

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSS.ID.C.7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tube has already baked 4 cakes, and he can bake 1 cake with each additional stick of butter he buys. Write an equation that shows the relationship between the number of additional sticks of butter x and the number of cakes y.

y=4xy=\left|4x\right|

y=x4y=\frac{x}{4}

y=4xy=4x

y=x+4y=x+4

Tags

CCSS.8.F.A.1

CCSS.8.F.A.3

CCSS.8.F.B.4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Con already owns 4 necklaces, and additional necklaces are priced at 1 for a dollar. Write an equation that shows the relationship between the money spent on additional necklaces x and the total number of necklaces y.

 y=4xy=4x  

 y=4x+1y=4x+1  

 y=x+4y=x+4  

 y=x4y=\frac{x}{4}  

Tags

CCSS.6.EE.C.9

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