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UH Turunan Fungsi Trigonometri

Authored by Hajjar Ekasari

Mathematics

12th Grade

CCSS covered

Used 33+ times

UH Turunan Fungsi Trigonometri
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Turunan pertama dari f(x)=4x36 sin xf\left(x\right)=4x^3-6\ \sin\ x adalah ....


 f(x)=12x2+6 sin xf'\left(x\right)=12x^2+6\ \sin\ x  

 f(x)=12x2+6 cos xf'\left(x\right)=12x^2+6\ \cos\ x  

 f(x)=12x26 cos xf'\left(x\right)=12x^2-6\ \cos\ x  

 f(x)=12x26 sin xf'\left(x\right)=12x^2-6\ \sin\ x  

 f(x)=12x36 cos xf'\left(x\right)=12x^3-6\ \cos\ x  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jika  f(x)=4cos2xf\left(x\right)=4\cos2x  maka nilai  f(60°)=...f'\left(60\degree\right)=... .

 43-4\sqrt{3}  

 23-2\sqrt{3}  

 3-\sqrt{3}  

 232\sqrt{3}  

 434\sqrt{3}  

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Turunan pertama dari f(x)=x3sinxf\left(x\right)=\frac{x^3}{\sin x}   adalah  f(x)=f'\left(x\right)=  ....

 x3sinx+3x2cosxx^3\sin x+3x^2\cos x  

 3x2sinx+x3cosx3x^2\sin x+x^3\cos x  

 3x2sinxx3cosx3x^2\sin x-x^3\cos x  

 3x2sinx+x3cosxsin2x\frac{3x^2\sin x+x^3\cos x}{\sin^2x}  

 3x2.sinxx3.cosxsin2x\frac{3x^2.\sin x-x^3.\cos x}{\sin^2x}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Turunan pertama dai fungsi f(x)= sin4(32x)f\left(x\right)=\ \sin^4\left(3-2x\right) adalah ....


 f(x)=4sin(64x)sin3(32x)f'\left(x\right)=-4\sin\left(6-4x\right)\sin^3\left(3-2x\right)  

 f(x)=4 sin(32x)sin2(32x) f'\left(x\right)=-4\ \sin\left(3-2x\right)\sin^2\left(3-2x\right)\   

 f(x)=4sin(64x) sin2(32x)f'\left(x\right)=-4\sin\left(6-4x\right)\ \sin^2\left(3-2x\right)  

 f(x)=8 cos (32x)sin3(32x)f'\left(x\right)=8\ \cos\ \left(3-2x\right)\sin^3\left(3-2x\right)  

 f(x)=8sin (32x)sin3(32x)f'\left(x\right)=8\sin\ \left(3-2x\right)\sin^3\left(3-2x\right)  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Gradien garis singgung kurva

 y=1+sin 2xy=1+\sin\ 2x  di titik  (π2,1)\left(\frac{\pi}{2},1\right)  adalah....

m = 2

m = 1

m = 0

m = -1

m = -2

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Persamaan garis singgung kurva         f(x)=2cos xf\left(x\right)=2\cos\ x  di titik   (π6,3)\left(\frac{\pi}{6},\sqrt{3}\right)     adalah ... .

 y=x+π6+3y=-x+\frac{\pi}{6}+\sqrt{3}  

 y=xπ6+3y=-x-\frac{\pi}{6}+\sqrt{3}  

 y=x+π63y=-x+\frac{\pi}{6}-\sqrt{3}  

 y=x+π6+3y=x+\frac{\pi}{6}+\sqrt{3}  

 y=x+π63y=x+\frac{\pi}{6}-\sqrt{3}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 f(x)f'\left(x\right) dari  f(x)=cos4xf\left(x\right)=\cos^4x  adalah...

 f(x)=4cos3xsinxf'\left(x\right)=4\cos^3x\sin x  

 f(x)=4cos3xsinxf'\left(x\right)=-4\cos^3x\sin x  

 f(x)=4cos2xsinxf'\left(x\right)=4\cos^2x\sin x  

 f(x)=8cos3xsinxf'\left(x\right)=-8\cos^3x\sin x  

 f(x)=8cos2xsinxf'\left(x\right)=8\cos^2x\sin x  

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