TERMOKIMIA

TERMOKIMIA

11th Grade

13 Qs

quiz-placeholder

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TERMOKIMIA

TERMOKIMIA

Assessment

Quiz

Chemistry

11th Grade

Practice Problem

Medium

Created by

Maria Yekiana Mulyahati

Used 248+ times

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13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Jika 4 mol karbon direaksikan dengan 4 mol gas hidrogen terbentuk 2 mol gas etena (C2H4) dan kalor yang dibutuhkan sebesar 104,6 kJ. Persamaan termokimianya adalah ….

4C(s) + 4H2(g) --> 2C2H4(g) ∆H = +209,2 kJ

4C(s) + 4H2(g) --> 2C2H4(g) ∆H = +104,6 kJ

4C(s) + 4H2(g) --> 2C2H4(g) ∆H = -104,6 kJ

2C(s) + 2H2(g) --> C2H4(g) ∆H = -52,3 kJ

2C(s) + 2H2(g) --> C2H4(g) ∆H = +52,3 kJ

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Perubahan entalpi pembentukan ( ∆Hf ) Kristal Na2SO4 ditunjukkan oleh reaksi ….

2NaOH(aq) + H2SO4(aq) --> Na2SO4(aq) + 2H2O(l)

2NaOH(aq) + H2SO4(aq) --> Na2SO4(kristal) + 2H2O(l)

Na2O(s) + SO2(g) --> Na2SO4(Kristal)

2Na(s) + 1/8 S8(s) +2O2(g) --> Na2SO4(Kristal)

16Na(s) + S8(s) + 16O2(g) --> 8Na2SO4(Kristal)

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Kalor yang dilepas atau dibutuhkan apabila 1 mol zat dibakar disebut ….

kalor lebur

kalor laten

kalor pembakaran

kalor peruraian

kalor netralisasi

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Jika diketahui : N2(g) + 3H2(g) --> 2NH3(g) ∆H = -92 kJ.

Perubahan entalpi pada peruraian 1 mol gas NH3 menjadi unsur-unsurnya adalah ….

- 92 kJ

- 46 kJ

+ 46 kJ

+ 92 kJ

+ 184 kJ

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Diketahui:

2NO(g) + O2(g) --> N2O4(g) ∆H = a kJ

NO(g) + ½ O2(g) --> NO2(g) ∆H = b kJ

Besarnya ∆H untuk reaksi:

2NO2(g) --> N2O4(g) adalah ….

(a + b) kJ

(a + 2b) kJ

(-a + 2b)

(2a + b) kJ

(a - 2b) kJ

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Dari siklus tersebut, AHf0 CH4 adalah ….

-571,6 kJ/mol

-393 kJ/mol

+571,6 kJ/mol

-74,8 kJ/mol

+74,8 kJ/mol

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Berdasarkan diagram berikut, harga ∆H3 adalah

∆H1 + ∆H2 - ∆H4

∆H1 - ∆H2 - ∆H4

∆H2 + ∆H4 - ∆H1

∆H1 + ∆H4 - ∆H2

∆H1 - ∆H2 + ∆H4

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