Search Header Logo

Основные тригонометрические тождества

Authored by Максим Дубина

Mathematics

10th Grade

Used 94+ times

Основные тригонометрические тождества
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Выберите верное(-ые) тождество(-а)

sinα+cosα=1\sin\alpha+\cos\alpha=1

sin2α+cos2α=1\sin^2\alpha+\cos^2\alpha=1

sin2α+cos2β=1\sin^2\alpha+\cos^2\beta=1

sin2αcos2α=1\sin^2\alpha-\cos^2\alpha=1

2.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Выберите верное(-ые) тождество(-а)

tgα=sinαcosαtg\alpha=\frac{\sin\alpha}{\cos\alpha}

tgα=cosαsinαtg\alpha=\frac{\cos\alpha}{\sin\alpha}

tgα=1ctgαtg\alpha=\frac{1}{\operatorname{ctg}\alpha}

tgα=1ctgαtg\alpha=1-\operatorname{ctg}\alpha

3.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Выберите верное(-ые) тождество(-а)

ctgα=sinαcosα\operatorname{ctg}\alpha=\frac{\sin\alpha}{\cos\alpha}

ctgα=cosαsinα\operatorname{ctg}\alpha=\frac{\cos\alpha}{\sin\alpha}

ctgα=1ctgα\operatorname{ctg}\alpha=\frac{1}{\operatorname{ctg}\alpha}

ctgα=1tgα\operatorname{ctg}\alpha=\sqrt{1-tg\alpha}

4.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Выберите верное(-ые) тождество(-а)

ctg2α=1cos2α1\operatorname{ctg}^2\alpha=\frac{1}{\cos^2\alpha}-1

tg2α=1cos2α1tg^2\alpha=\frac{1}{\cos^2\alpha}-1

tg2α=1sin2α1tg^2\alpha=\frac{1}{\sin^2\alpha}-1

ctg2α=1sin2α1\operatorname{ctg}^2\alpha=\frac{1}{\sin^2\alpha}-1

5.

MULTIPLE SELECT QUESTION

1 min • 1 pt

Выберите верное(-ые) тождество(-а)

tg αctgα=1tg\ \alpha\cdot\operatorname{ctg}\alpha=1

tg α+ctgα=1tg\ \alpha+\operatorname{ctg}\alpha=1

tg2 α+ctg2α=1tg^2\ \alpha+\operatorname{ctg}^2\alpha=1

tg2 αctgα=1tg^2\ \alpha\cdot\operatorname{ctg}\alpha=1

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Упростите выражение

 1cos2α=1-\cos^2\alpha=  

 cos2α\cos^2\alpha  

 1sin2α1-\sin^2\alpha  

 sin2α\sin^2\alpha  

 00  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Упростите выражение

 tg αcosα=tg\ \alpha\cdot\cos\alpha=  

 sinα\sin\alpha  

 cosα\cos\alpha  

 ctgα\operatorname{ctg}\alpha  

 tgαtg\alpha  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

Already have an account?