
Kinematic EQs 10/8
Authored by Stacy King
Physics
10th - 12th Grade
Used 4+ times

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18 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway? (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the deck to the street below. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration). (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2, determine the speed of the Jaguar before it began to skid. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car (assume uniform acceleration) (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
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