
Kinematics

Quiz
•
Physics
•
11th - 12th Grade
•
Medium
Standards-aligned
Stacy King
Used 3+ times
FREE Resource
7 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
What is Kinematics?
The study of motion without reference to forces and masses.
The measure that separates two points.
A course taken by an object.
Ratio between time and speed.
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A car is NOT accelerating if it is moving
at constant velocity
only as influenced by gravity
in a circle
at increasing speed
Tags
NGSS.HS-PS2-1
NGSS.HS-PS2-2
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A drag racer accelerates from rest at a rate of +7.2 m/s2 for +125.0 m. What equation do you need to find his final velocity?(v= the change in velocity)(d=displacement)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
An object accelerates from rest, with a constant acceleration of 8.4 m/s2 , what will its velocity be after 11s? (v= the change in velocity)(d=displacement)
a=v/t
d=vi(t)+1/2a(t2)
vf2=vi2+2ad
d=[(vi+vf)/2]t
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the deck to the street below. (d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A bowling ball is dropped on the Jupiter from a height of 3 meters with an initial velocity of 0.4 m/s. The acceleration of gravity on Jupiter is 24.5 m/s2 . How long does it take for the bowling ball to reach the surface of Jupiter?
(d=the displacement) (v= the change in velocity)
a=v/t
vf2=vi2+2ad
d=0.5(vi+vf)t
d=vit+0.5at2
vf=vi+at
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Two objects are dropped from a bridge, an interval of 1.0 s apart. Air resistance is negligible. During the time that both objects continue to fall, their separation
increases
decreases
increase initially, then remains constant
decreases initially, then remains constant
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