Writing Equations from Roots

Which equation has ONLY the following roots?

x = {-2,7,3}

• y = (x-2)(x+7)(x+3)

• y = (x+2)(x-7)(x-3)

• y = -2x²+7x+3

• y = 2x²-7x-3

• y = (x+2)(x-7)(x-3)(x)

What could be the equation of the graph shown here?

• y = (x+3)(x+1)

• y = (x-3)(x-1)

• y = (x+3)²(x+1)³

• y = (x+3)³(x+1)²

Which equation has the roots

 $x=\pm2i,\ x=1$  ?

•  $y=\left(x^2+2\right)\left(x-1\right)$  
  

•  $y=\left(x^2+2\right)\left(x+1\right)$  

•  $y=\left(x^2+4\right)\left(x-1\right)$  

•  $y=\left(x^2+4\right)\left(x+1\right)$   
  

Which could be the equation of the graph shown here?

• y = (x²+4x+10)(x-8)

• y = x-8

• y = x+8

• y = (x²+4x+10)(x+8)

Choose all of the equations here would have roots at ONLY

 $x=\pm\sqrt{3},\ x=2$  .

•  $y=\left(x+3\right)\left(x-3\right)\left(x+2\right)$  

•  $y=\left(x+3\right)\left(x-3\right)\left(x-2\right)$  

•  $y=\left(x^2-3\right)\left(x-2\right)\left(x+5\right)$  

•  $y=\left(x^2-3\right)\left(x-2\right)$  

•  $y=x^3-2x^2-3x+6$  

Which equation has zeros at

 $x=1\pm2\sqrt{5},\ x=0$  ?

•  $y=x^2\left(x^2-11\right)$  

•  $y=x^2\left(x^2-2x-9\right)$  

•  $y=x^3\left(x^2-2x-19\right)$  

•  $y=x^3\left(x^2+2x-19\right)$  

What equation has roots at

 $x=0,\ x=\pm i\sqrt{6},\ x=5$  ?

•  $y=x\left(x^2+6\right)\left(x-5\right)$  

•  $y=x\left(x^2-6\right)\left(x-5\right)$  

•  $y=x\left(x^2+6\right)\left(x+5\right)$  

•  $y=x\left(x^2-6\right)\left(x+5\right)$  

Tags

CCSS.HSA.APR.B.3

Which of the equations match the graph shown here?

• y = (x-2)(x-1)(x+1)

• y = (x-2)(x-1)(x+1)²

• y = (x-2)(x-1)²(x+2)

• y = -(x-2)(x-1)(x+1)²

• y = -(x-2)(x-1)²(x+1)

Which equation has the roots

 $x=3,\ x=2\pm3i\sqrt{7}$  ?

•  $y=\left(x-3\right)\left(x^2+59\right)$  

•  $y=\left(x+3\right)\left(x^2+59\right)$  

•  $y=\left(x-3\right)\left(x^2-4x+67\right)$  

•  $y=\left(x+3\right)\left(x^2-4x+67\right)$  

Which equation has the roots

 $x=\left\{-12,\ 130,\ 3\pm\sqrt{14}\right\}$  ?

•  $y=\left(x-3\right)\left(x+12\right)\left(x-130\right)\left(x^2-14\right)$  

•  $y=\left(x+12\right)\left(x-130\right)\left(x^2-6x-5\right)$  

•  $y=\left(x-12\right)\left(x+130\right)\left(x^2-6x-5\right)$  

•  $y=\left(x+3\right)\left(x-12\right)\left(x+130\right)\left(x^2-14\right)$