Solving Quadratics

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Convert $3x^2+17x=28$ to factored form and identify the solution.

•  $\left(3x-4\right)\left(x+7\right);\ x\ =\frac{4}{3},\ -7$  

•  $\left(x-4\right)\left(x+7\right);\ x\ =\ 4,-\ 7$  
  

•  $x\left(3x+17\right)=28;\ x=0,-\frac{17}{3}$  
  

• Not factorable

What is the standard form for a Quadratic?

• $ax^2+bx=-c$
  

• $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

  
  

• $ax^2+bx+c=0$
  

• y = mx + b

What are the solutions?

• -2, 1
• 1, 2
• -1,2
• 0,-4

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

 $Solve\ \ 2x^2-3=-89\ \$ using any method.

• -43

•  $\pm2i\sqrt{22}$  
  

•  $\pm i\sqrt{43}$  

• none of the above
  

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

 $Use\ the\ quadratic\ formula\ to\ solve\ 2x^2+x=-4x+36\ for\ x.\$  

•  $\frac{-5\pm i\sqrt{263}}{4}$  
  

•  $\frac{-5\pm\sqrt{313}}{4}$  
  

• 18, 31
  

•  $\frac{5\pm\sqrt{313}}{4}$  
  

Miked solved the equation x² + 8x = 14 by completing the square. Which of the following equations is part of the correct solution.

• (x + 4)² = 14

• (x + 4)² = 18

• (x + 4)² = 30

• (x - 4)² = 30

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:

x² + 4x - 12 = 2

(x - 2)(x + 6) = 2,

by setting x -2 = 0 and x + 6 = 0.

Her solutions are x = 2 and x = -6.

Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong.

Tags

CCSS.HSA-REI.B.4B

Simplify i⁶³

• i

• -i

• 1

• -1

Tags

CCSS.HSN.CN.A.2

Simplify.  $\sqrt{-108}$  

•  $3i\sqrt{6}$  
  

•  $3i\sqrt{20}$  
  

•  $6i\sqrt{3}$  
  

• undefined