s e n θ = 3 2 sen\theta=\frac{\sqrt{3}}{2} s e n θ = 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> sus soluciones son

θ = 60 ° y 120 ° \theta=\ 60°\ y\ 120° θ = 6 0 ° y 1 2 0 °

θ = 30 ° y 150 ° \theta=\ 30°\ \ \ y\ 150° θ = 3 0 ° y 1 5 0 °

θ = 210 ° y 130 ° \theta=210°\ \ y\ 130° θ = 2 1 0 ° y 1 3 0 °

Calcula el valor del ángulo s e n θ = − 2 2 sen\theta=-\frac{\sqrt{2}}{2} s e n θ = − 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

θ = 225 ° y 315 ° \theta=\ 225°\ y\ 315°\ θ = 2 2 5 ° y 3 1 5 °

θ = 112 ° y 213 ° \theta=112°\ y\ \ 213° θ = 1 1 2 ° y 2 1 3 °

θ = 187 ° y 224 ° \theta=\ 187°\ y\ 224° θ = 1 8 7 ° y 2 2 4 °

cos ⁡ θ = − 1 \cos\theta=-1 cos θ = − 1

θ = 180 ° \theta=180°\ θ = 1 8 0 °

θ = 360 ° \theta=360° θ = 3 6 0 °

cos ⁡ θ = 1 4 \cos\theta=\frac{1}{4} cos θ = 4 1

θ ≈ 75.5224 ° y 284.4776 ° \theta\approx75.5224°\ y\ 284.4776° θ ≈ 7 5 . 5 2 2 4 ° y 2 8 4 . 4 7 7 6 °

θ ≈ 54.3456 ° y 231.3245 ° \theta\approx54.3456°\ y\ 231.3245° θ ≈ 5 4 . 3 4 5 6 ° y 2 3 1 . 3 2 4 5 °

θ ≈ 43.87456 ° y 76.9856 ° \theta\approx43.87456°\ y\ 76.9856° θ ≈ 4 3 . 8 7 4 5 6 ° y 7 6 . 9 8 5 6 °

tan ⁡ θ = 5 \tan\theta=5 tan θ = 5

θ ≈ 78.6900 ° y 258.6900 ° \theta\approx78.6900°\ y\ \ 258.6900° θ ≈ 7 8 . 6 9 0 0 ° y 2 5 8 . 6 9 0 0 °

θ ≈ 56.7467 ° y 76.8976 ° \theta\approx56.7467\ °\ y\ 76.8976° θ ≈ 5 6 . 7 4 6 7 ° y 7 6 . 8 9 7 6 °

θ ≈ 55.6545 ° y 230.6789 ° \theta\approx55.6545°\ y\ 230.6789° θ ≈ 5 5 . 6 5 4 5 ° y 2 3 0 . 6 7 8 9 °

2 s e n θ + 1 = 0 \sqrt{2}sen\theta+1=0 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> s e n θ + 1 = 0

θ = 225 ° y 315 ° \theta=\ 225°\ y\ 315° θ = 2 2 5 ° y 3 1 5 °

θ = 200 ° y 320 ° \theta=200°\ y\ 320° θ = 2 0 0 ° y 3 2 0 °

θ = 120 ° y 312 ° \theta=\ 120°\ y\ 312° θ = 1 2 0 ° y 3 1 2 °

θ = 123 ° y 234 ° \theta=\ 123°\ y\ 234° θ = 1 2 3 ° y 2 3 4 °

Una ecuación trigonometrica es:

Es una igualdad entre dos expresiones trigonometricas

Es una igualdad en la que se conocen todos los términos.

Es una desigualdad en la que se desconoce un término

¿Qué calculamos al resolver una ecuación trigonométrica que la caracteriza como tal?

Los valores de los ángulos que resuelven dicha expresión

El valor de un ángulo que resuelve la ecuación

Los ángulos que resuelven la expresión

La circunferencia trigonométrica sirve para:

visualizar el ángulo y el signo de la razón trigonométrica correspondiente asociada.

indicar los ángulos en el sentido positivo.

indicar los ángulos en el sentido negativo

ECUACIONES LINEALES TRIGONOMETRICAS

Authored by Maritza Gonzalez

Mathematics

10th Grade

CCSS covered

Used 21+ times

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14 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$3Tan^2\theta-1=0,\ tiene\ como\ soluciones$

{30º,150º}

{30º,210º}

{150º, 210º}

{30º,150º,210º,330º}

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Cos\theta Tan\theta-Tan\theta=0,\ tiene\ como\ suluciones$

$\left[90º,270º\right]$

$\left\{0º,180º\right\}$

$\left\{0º,90º\right\}$

$\left\{90º,180º\right\}$

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

$\theta=\ 30°\ \ \ y\ 150°$

$\theta=210°\ \ y\ 130°$

$\theta=\ 60°\ y\ 120°$

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calcula el valor del ángulo $sen\theta=-\frac{\sqrt{2}}{2}$

$\theta=\ 225°\ y\ 315°\$

$\theta=112°\ y\ \ 213°$

$\theta=\ 187°\ y\ 224°$

No existe

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\theta=-1$

$\theta=180°\$

$\theta=0°$

$\theta=360°$

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\theta=\frac{1}{4}$

$\theta\approx75.5224°\ y\ 284.4776°$

$\theta\approx54.3456°\ y\ 231.3245°$

$\theta\approx43.87456°\ y\ 76.9856°$

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\tan\theta=5$

$\theta\approx78.6900°\ y\ \ 258.6900°$

$\theta\approx56.7467\ °\ y\ 76.8976°$

$\theta\approx55.6545°\ y\ 230.6789°$

Tags

CCSS.HSF.TF.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sqrt{2}sen\theta+1=0$

$\theta=200°\ y\ 320°$

$\theta=\ 225°\ y\ 315°$

$\theta=\ 120°\ y\ 312°$

$\theta=\ 123°\ y\ 234°$

Tags

CCSS.HSF.TF.B.7

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Dada la siguiente Ecuación Trigonométrica, indica el valor de x.
$2\cos\left(x\right)+4=5\$

error math

60°

-60°

120°

Tags

CCSS.HSF.TF.B.7

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ECUACIONES LINEALES TRIGONOMETRICAS

3Tan2θ−1=0, tiene como soluciones3Tan^2\theta-1=0,\ tiene\ como\ soluciones3Tan2θ−1=0, tiene como soluciones

CosθTanθ−Tanθ=0, tiene como sulucionesCos\theta Tan\theta-Tan\theta=0,\ tiene\ como\ sulucionesCosθTanθ−Tanθ=0, tiene como suluciones

senθ=32sen\theta=\frac{\sqrt{3}}{2}senθ=23​​ sus soluciones son

Calcula el valor del ángulo senθ=−22sen\theta=-\frac{\sqrt{2}}{2}senθ=−22​​

cos⁡θ=−1\cos\theta=-1cosθ=−1

cos⁡θ=14\cos\theta=\frac{1}{4}cosθ=41​

tan⁡θ=5\tan\theta=5tanθ=5

2senθ+1=0\sqrt{2}sen\theta+1=02​senθ+1=0

Una ecuación trigonometrica es:

Dada la siguiente Ecuación Trigonométrica, indica el valor de x. 2cos⁡(x)+4=5 2\cos\left(x\right)+4=5\ 2cos(x)+4=5

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$3Tan^2\theta-1=0,\ tiene\ como\ soluciones$

$Cos\theta Tan\theta-Tan\theta=0,\ tiene\ como\ suluciones$

$sen\theta=\frac{\sqrt{3}}{2}$ sus soluciones son

Calcula el valor del ángulo $sen\theta=-\frac{\sqrt{2}}{2}$

$\cos\theta=-1$

$\cos\theta=\frac{1}{4}$

$\tan\theta=5$

$\sqrt{2}sen\theta+1=0$

Dada la siguiente Ecuación Trigonométrica, indica el valor de x.
$2\cos\left(x\right)+4=5\$