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Laws of Sine

Authored by Krista Sanders krista.sanders@apsk12.org

Mathematics

10th - 12th Grade

CCSS covered

Used 8+ times

Laws of Sine
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10 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Use the Law of Sines to solve for BC

33
24
12
29

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the measure of angle A?

58 degrees
61 degrees
78 degrees
74 degrees

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Find AC

12
10
23
14

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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What would be the BEST way to solve for p?

Pythagorean Theorem

Law of Sines

Law of Cosines

 sin32°=p21\sin32\degree=\frac{p}{21}  

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

5.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

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Which two ratios would you need to use the Law of Sines to find b? (Select 2)

 sin50°b\frac{\sin50\degree}{b}  

 sinAa\frac{\sin A}{a}  

 sin110°12\frac{\sin110\degree}{12}  

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which of the following is the correct set up of the Law of Sines formula for this triangle?

 sin20°a=sin50°b=sin110°12\frac{\sin20\degree}{a}=\frac{\sin50\degree}{b}=\frac{\sin110\degree}{12}  

 sinAa=sinb50=sin110°12\frac{\sin A}{a}=\frac{\sin b}{50}=\frac{\sin110\degree}{12}  

 sin20°A=sin50°b=sin12110°\frac{\sin20\degree}{A}=\frac{\sin50\degree}{b}=\frac{\sin12}{110\degree}  

 sinAa=sin110°b=sin50°12\frac{\sin A}{a}=\frac{\sin110\degree}{b}=\frac{\sin50\degree}{12}  

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Use the Law of Sines to find a.
Round your answer to the nearest tenths place.

4.4

12.8

0.6

20

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

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