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Nonlinear & Rational Inequalites

Authored by Enrique Waldo

Mathematics

11th - 12th Grade

CCSS covered

Used 87+ times

Nonlinear & Rational Inequalites
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x290x^2-9\le0  

 (,3)(3,)\left(-\infty,-3\right)\cup\left(3,\infty\right)  

 (3,3)\left(-3,3\right)  

 [,3][3,]\left[-\infty,-3\right]\cup\left[3,\infty\right]  

 [3,3]\left[-3,3\right]  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x+2x43\frac{x+2}{x-4}\ge3  

 (,4)(7,)\left(-\infty,4\right)\cup\left(7,\infty\right)  

 (4,7]\left(4,7\right]  

 [,4][7,]\left[-\infty,4\right]\cup\left[7,\infty\right]  

 [4,7)\left[4,7\right)  

Tags

CCSS.HSA.REI.A.2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x2x12>0x^2-x-12>0  

 (,3)(4,)\left(-\infty,-3\right)\cup\left(4,\infty\right)  

 (3,4)\left(-3,4\right)  

 [,3][4,]\left[-\infty,-3\right]\cup\left[4,\infty\right]  

 [3,4]\left[-3,4\right]  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 3x2x2+41.5\frac{3x^2}{x^2+4}\ge1.5  

 (,2)(2,)\left(-\infty,-2\right)\cup\left(2,\infty\right)  

 (2,2)\left(-2,2\right)  

 (,2][2,)\left(-\infty,-2\right]\cup\left[2,\infty\right)  

 [2,2]\left[-2,2\right]  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x211x+12<0-x^2-11x+12<0  

 (,12)(1,)\left(-\infty,-12\right)\cup\left(1,\infty\right)  

 (12,1)\left(-12,1\right)  

 (,12][1,)\left(-\infty,-12\right]\cup\left[1,\infty\right)  

 [12,1]\left[-12,1\right]  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x+6x+120\frac{x+6}{x+1}-2\ge0  

 (,1)(4,)\left(-\infty,-1\right)\cup\left(4,\infty\right)  

 (1,4]\left(-1,4\right]  

 (,1][4,)\left(-\infty,-1\right]\cup\left[4,\infty\right)  

 [1,4]\left[-1,4\right]  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve the inequality in interval notation

 x28x+15>0x^2-8x+15>0  

 (,3)(5,)\left(-\infty,3\right)\cup\left(5,\infty\right)  

 (3,5)\left(3,5\right)  

 (,3][5,)\left(-\infty,3\right]\cup\left[5,\infty\right)  

 [3,5]\left[3,5\right]  

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