Derivadas parciales Mating-1

Derivadas parciales Mating-1

University - Professional Development

10 Qs

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Derivadas parciales Mating-1

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Assessment

Quiz

Mathematics

University - Professional Development

Easy

Created by

Juan Flores

Used 3+ times

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10 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Sea la función

 F(x,y)=x2y22xy2F(x,y)=x^2y^2−2xy^2  
Determine el valor de  Fx\frac{\partial F}{\partial x}  como  Fy\frac{\partial F}{\partial y}  en el punto  P(2,1)P\left(2,1\right)  


 Fx=2\frac{\partial F}{\partial x}=2   Fy=0\frac{\partial F}{\partial y}=0  

 \frac{\partial F}{\partial x}=2   Fy=2\frac{\partial F}{\partial y}=2  

 Fx=0\frac{\partial F}{\partial x}=0   \frac{\partial F}{\partial y}=0  

 Fx=0\frac{\partial F}{\partial x}=0   Fy=2\frac{\partial F}{\partial y}=2  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Sea la función

 θ(r,s)=r2+s2+rs\theta(r,s)=\sqrt{r^2+s^2}+\frac{r}{s}  
Determine el valor de  θr\frac{\partial\theta}{\partial r}  como  θs\frac{\partial\theta}{\partial s}  en el punto  P(3,4)P\left(3,4\right)  

 θr=2720\frac{\partial\theta}{\partial r}=\frac{27}{20}   \frac{\partial\theta}{\partial s}=\frac{49}{80} 

 \frac{\partial\theta}{\partial r}=\frac{17}{20}   θs=3980\frac{\partial\theta}{\partial s}=\frac{39}{80} 

 θr=1720\frac{\partial\theta}{\partial r}=\frac{17}{20}   θs=4980\frac{\partial\theta}{\partial s}=\frac{49}{80} 

 θr=3120\frac{\partial\theta}{\partial r}=\frac{31}{20}   \frac{\partial\theta}{\partial s}=\frac{49}{80} 

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Sea la función

 F(x,y)=3x3y2x2y2+y3F\left(x,y\right)=3x^3y-2x^2y^2+y^3  
Determine el valor de  Fx\frac{\partial F}{\partial x}  como  Fy\frac{\partial F}{\partial y}  en el punto  P(1,2)P\left(1,-2\right)  

 Fx=34\frac{\partial F}{\partial x}=-34   Fy=23\frac{\partial F}{\partial y}=23 

 Fx=34\frac{\partial F}{\partial x}=34   Fy=23\frac{\partial F}{\partial y}=-23 

 Fx=34\frac{\partial F}{\partial x}=-34   Fy=23\frac{\partial F}{\partial y}=-23 

 Fx=34\frac{\partial F}{\partial x}=34   Fy=23\frac{\partial F}{\partial y}=23 

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Sea la función

 F(x,y)=ln(1+2x2+3y2)F\left(x,y\right)=\ln(1+2x^2+3y^2)  
Determine el valor de  Fx\frac{\partial F}{\partial x}  como  Fy\frac{\partial F}{\partial y}  en el punto  P(1,2)P\left(1,2\right)  

 Fx=415\frac{\partial F}{\partial x}=-\frac{4}{15}   Fy=45\frac{\partial F}{\partial y}=-\frac{4}{5} 

 Fx=415\frac{\partial F}{\partial x}=\frac{4}{15}   Fy=45\frac{\partial F}{\partial y}=-\frac{4}{5} 

 Fx=415\frac{\partial F}{\partial x}=\frac{4}{15}   Fy=45\frac{\partial F}{\partial y}=\frac{4}{5} 

 Fx=45\frac{\partial F}{\partial x}=\frac{4}{5}   Fy=415\frac{\partial F}{\partial y}=\frac{4}{15} 

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Sea la función

 F(x,y)=ex(2y2x2)F\left(x,y\right)=e^{-x}(2y^2−x^2)  
Determine el valor de  Fx\frac{\partial F}{\partial x}  como  Fy\frac{\partial F}{\partial y}  en el punto  P(1,2)P\left(1,2\right)  

 Fx=1.019978389\frac{\partial F}{\partial x}=1.019978389   Fy=1.839397205\frac{\partial F}{\partial y}=-1.839397205 

 Fx=1.839397205\frac{\partial F}{\partial x}=1.839397205   Fy=1.019978389\frac{\partial F}{\partial y}=1.019978389 

 Fx=1.839397205\frac{\partial F}{\partial x}=-1.839397205   Fy=1.019978389\frac{\partial F}{\partial y}=1.019978389 

 Fx=1.019978389\frac{\partial F}{\partial x}=1.019978389   Fy=1.839397205\frac{\partial F}{\partial y}=1.839397205 

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Dada la función z = f(x,y) en forma implícita, hallar ∂z/∂y.

Media Image
Media Image
Media Image
Media Image

Es otra expresión.

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Obtener

 Fx\frac{\partial F}{\partial x}  de la función  F=(z2+1)xF=\left(z^2+1\right)^x  

 (z2+1)xln(z2+1)\left(z^2+1\right)^x\ln\left(z^2+1\right)  

 (z2+1)xln(z2+1)x\left(z^2+1\right)^x\ln\left(z^2+1\right)x  

 (z2+1)xln(x)\left(z^2+1\right)^x\ln\left(x\right)  

 x(z2+1)x1(2z)x\left(z^2+1\right)^{x-1}\left(2z\right)  

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