Solving Exponential and Logarithmic Equations

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CCSS.HSA.REI.A.1

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CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.4

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CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

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CCSS.HSA.REI.A.1

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CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.4

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CCSS.HSF.BF.B.5

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CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

2 * 4^{3x – 6} – 8 = 120

• x = 3
• x = 4
• x = 2.9
• x = 8

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CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.SSE.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

To solve, 16^5x = 64^x+7, what would be the correct set-up?

There is more than one correct answer.

• 4^4(5x)=4^16(x+7)

• 8^2(5x)=8^8(x+7)

• 4^2(5x)=4^3(x+7)

• 2^4(5x)=2^6(x+7)

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CCSS.HSA.CED.A.1