Latihan Soal Trigonometri Kelas XI

Latihan Soal Trigonometri Kelas XI

11th Grade

10 Qs

quiz-placeholder

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Latihan Soal Trigonometri Kelas XI

Latihan Soal Trigonometri Kelas XI

Assessment

Quiz

Mathematics

11th Grade

Medium

Created by

Linda Lasmawati Silalahi

Used 310+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

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2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

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3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari 4 sin 22,50 cos 22,50 adalah ....

424\sqrt{2}

222\sqrt{2}

2\sqrt{2}

122\frac{1}{2}\sqrt{2}

142\frac{1}{4}\sqrt{2}

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 cosAcosB=\cos A-\cos B=  ... (*Operasi Trigonometri)

 2sin12(A+B)cos12(AB)2\sin\frac{1}{2}\left(A+B\right)\cos\frac{1}{2}\left(A-B\right)  

 2cos12(A+B)sin12(AB)2\cos\frac{1}{2}\left(A+B\right)\sin\frac{1}{2}\left(A-B\right)  

 2cos12(A+B)cos12(AB)2\cos\frac{1}{2}\left(A+B\right)\cos\frac{1}{2}\left(A-B\right)  

 2sin12(A+B)sin12(AB)-2\sin\frac{1}{2}\left(A+B\right)\sin\frac{1}{2}\left(A-B\right)  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Hasil dari sin50°+sin40°\sin50\degree+\sin40\degree  adalah...


 2sin45°cos5°2\sin45\degree\cos5\degree  

 2cos45°sin5°2\cos45\degree\sin5\degree  

 2cos45°cos5°2\cos45\degree\cos5\degree  

 2sin45°sin5°2\sin45\degree\sin5\degree  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Hasil  dari

 sin40°cos30°\sin40\degree\cos30\degree  adalah... 

 12(sin70°+sin10°)\frac{1}{2}\left(\sin70\degree+\sin10\degree\right)  

 12(sin70°sin10°)\frac{1}{2}\left(\sin70\degree-\sin10\degree\right)  

 12(cos70°+cos10°)\frac{1}{2}\left(\cos70\degree+\cos10\degree\right)  

 12(cos70cos10°)-\frac{1}{2}\left(\cos70-\cos10\degree\right)  

7.

MULTIPLE CHOICE QUESTION

5 mins • 12 pts

 cos θ   =12,  untuk  00  θ 3600  adalah ...\cos\ \theta\ \ \ =-\frac{1}{2},\ \ untuk\ \ 0^0\ \le\ \theta\ \le360^0\ \ adalah\ ... 

Himpunan penyelesaian dari persamaan di atas  adalah ... 

  {1200 dan 2400}\left\{120^0\ dan\ 240^0\right\}  

 {1500 dan 2100}\left\{150^0\ dan\ 210^0\right\}  

 {1200 dan 2100}\left\{120^0\ dan\ 210^0\right\}  

 {600 , 2400}\left\{60^0\ ,\ 240^0\right\}  

 {600, 1200}\left\{60^0,\ 120^0\right\}  

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