Solving Systems by ELIMINATION (Lesson 3-3)

The goal of solving a system using the ELIMINATION method is to have one of the variables (x or y) __________.

• Multiply

• Add

• Cancel

• Substitute

What is the 1st step of solving a system using the ELIMINATION method?

• Look for or Create a set of opposites

• Write both equations in slope-intercept form

• Solve for one of the variables

What is the 2nd step of solving a system using the ELIMINATION method?

• DIVIDE the equations together

• MULTIPLY the equations together

• SUBTRACT the equations together

• ADD the equations together

After ADDING the two equations, what would be the result?

 $5x\ +\ 3y\ =\ 8$ 
 $5x\ -\ 3y\ =\ 2$  

• 10x = 10

• 0 = 10

• 6y = -6

• 10x + 6y = 10

Solve the system completely using the ELIMINATION method.

 $5x\ +\ 3y\ =\ 8$ 
 $5x\ -\ 3y\ =\ 2$  

• (1, -1)

• (1, 1)

• (-1, 1)

• No Solution

To cancel the y's, you would need to multiply the 2nd equation by ____

 $10x\ +\ 2y\ =\ 4$  
 $5x\ -\ y\ =\ -12$  

• Multiply by  3

• Multiply by  -3

• Multiply by -2

• Multiply by  2

Solve the system using the ELIMINATION method

 $10x\ +\ 2y\ =\ 4$  
 $5x\ -\ y\ =\ -12$  

• (1, 7)

• (7, 1)

• (7, -1)

• (-1, 7)

Solve the system using the ELIMINATION method

 $-6x\ -\ 9y\ =\ -18$  
 $5x\ +\ 7y\ =\ 17$  

• (9, 4)

• (4, 9)

• (9, -4)

• (-4, 9)

Solve the system using the ELIMINATION method

 $6x\ -\ 4y\ =\ 10$  
 $-3x\ +\ 2y\ =\ -5$  

• (0, 0)

• (1, 1)

• No Solution  $\phi$  

• Infinite Solutions $\infty$  

Solve the system using the ELIMINATION method

 $4x\ -\ 6y\ =\ -26$  
 $-2x\ +\ 3y\ =\ -13$  

• (0, 0)

• (0, -52)

• No Solution  $\phi$  

• Infinite Solutions $\infty$