Synthetic Division

• 0

• 1

• 2

• 3

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CCSS.HSA.APR.D.6

If you are missing an exponent in your polynomial you must put a zero as a coefficient place holder for that exponent

• True

• False

It's time to write the answer. What goes in the yellow area?

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CCSS.HSA.APR.D.6

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• 
  Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

Was this problem done correctly?

• Yes

• No

Tags

CCSS.HSA.APR.D.6

• 
  3   0   -4   6   1

• 6   -4   3   1   0

• -6   4   0   -3   -1

• 6   -4   0   3   1

Tags

CCSS.HSA.APR.D.6

What is the next step in synthetic division?

• Add the 9 and 6

• Multiply the 9 and 6

• Bring down the -48

Tags

CCSS.HSA.APR.D.6

What is the proper way to write the answer for the following problem?

• 
  2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 
  2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.D.6

(2x³ + 5x² + 9) ÷ (x + 3)

• 2x² - x + 3
• 2x³ - x² + 3x
• 2x² + 11x + 33 + 108/x+3
• 2x² - 5x + 12

Tags

CCSS.HSA.APR.D.6

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9
• 3x² - 3x + 8 - 9/x+1
• 3x² + 3x + 8 + 7/x+1
• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6