5.a Chain Rule

5.a Chain Rule

11th - 12th Grade

9 Qs

quiz-placeholder

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5.a Chain Rule

5.a Chain Rule

Assessment

Quiz

Mathematics

11th - 12th Grade

Easy

CCSS
HSA.SSE.A.2, HSF.BF.B.5, HSA.SSE.B.3

+7

Standards-aligned

Created by

Thomas Barbieri

Used 33+ times

FREE Resource

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of  f(x) = (x6 + 4)5
f '(x) = 5x5(x4 + 4)4
f '(x) = 6x5(x6 + 4)4
f '(x) = 30x5(x6 + 4)4
f '(x) = 30x6(x6 + 4)4

2.

MULTIPLE CHOICE QUESTION

15 mins • 12 pts

Media Image

A

B

C

D

Tags

CCSS.HSA.SSE.A.2

CCSS.HSN.RN.A.2

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

find y' for y=e5x + 1

5e5x+1

e5x

5e5x

1

Tags

CCSS.HSF-IF.C.8B

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

find y' for y= sin(2x2)

4sin(2x2)

4xcos(2x2)

2xcos(2x2)

xcos(4x2)

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 f(x) = ln(2x6)f\left(x\right)\ =\ \ln\left(2x^6\right)  

 6x\frac{6}{x}  

 x6\frac{x}{6}  

6x

 6x5\frac{6x}{5}  

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

CCSS.HSF.LE.A.4

6.

MULTIPLE CHOICE QUESTION

15 mins • 12 pts

Media Image
Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 drdt if r=(secθ+tanθ)3\frac{dr}{dt}\ if\ r=\left(\sec\theta+\tan\theta\right)^{-3}  Find

 3secθ(secθ+tanθ)3\frac{-3\sec\theta}{\left(\sec\theta+\tan\theta\right)^3}  

 3(secθ+tanθ)4(tan2θ+secθtanθ)-3\left(\sec\theta+\tan\theta\right)^{-4}\left(\tan^2\theta+\sec\theta\tan\theta\right)  

 3(secθ+tanθ)4-3\left(\sec\theta+\tan\theta\right)^{-4}  

 3(secθ+tanθ+sec2θ)4-3\left(\sec\theta+\tan\theta+\sec^2\theta\right)^{-4}  

Tags

CCSS.HSA.SSE.B.3

8.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is f'(x) if f(x) = cos(5x4)?
f'(x) = sin(20x3)
f'(x) = 20x3 sin(5x4)
f'(x) = -sin(20x3)
f'(x) = -20x3 sin(5x4)

9.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 f(x) = log6(x35x)f\left(x\right)\ =\ \log_6\left(x^3-5x\right)  

 2x35ln(6)(x35x)\frac{2x^3-5}{\ln\left(6\right)\cdot\left(x^3-5x\right)}  

 3x25ln(6)(3x25)\frac{3x^2-5}{\ln\left(6\right)\cdot\left(3x^2-5\right)}  

 2x35ln(6)(3x25)\frac{2x^3-5}{\ln\left(6\right)\cdot\left(3x^2-5\right)}  

 3x25ln(6)(x35x)\frac{3x^2-5}{\ln\left(6\right)\cdot\left(x^3-5x\right)}  

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.IF.A.1