Finding the Vertex of a Parabola

Find the vertex of:

 $y=x^2+16x+71$  

• (8, 7)
  

• (-8, 7)

• (7, 8)

• (7, -8)

Answer explanation

Remember: in standard form these are two part questions, you need to find your x value first by doing  $x=\frac{-b}{2a}$  , and then what number you get there you plug into your equation for x and solve for y.

Find the vertex:

 $y=x^2-2x-5$  

• (-1, -6)

• (-1, 6)

• (1, -6)

• (1, 6)

Answer explanation

Remember: in standard form these are two part questions, you need to find your x value first by doing  $x=\frac{-b}{2a}$  , and then what number you get there you plug into your equation for x and solve for y.

Find the vertex:

 $y=-x^2-14x-59$  

• (-10, 7)

• (-7, 10)

• (-7, -10)

• (10, 7)

Answer explanation

Remember: in standard form these are two part questions, you need to find your x value first by doing  $x=\frac{-b}{2a}$  , and then what number you get there you plug into your equation for x and solve for y.

Find the vertex:

 $y=x^2+4x+0$  

• (0, 0)

• (2, 4)

• (-2, -4)

• (1, 4)

Answer explanation

Remember: in standard form these are two part questions, you need to find your x value first by doing  $x=\frac{-b}{2a}$  , and then what number you get there you plug into your equation for x and solve for y.

Find the vertex:

 $y=x^2-6x+5$  

• (3, 5)

• (-3, 5)

• (3, 4)

• (3, -4)

Answer explanation

Remember: in standard form these are two part questions, you need to find your x value first by doing  $x=\frac{-b}{2a}$  , and then what number you get there you plug into your equation for x and solve for y.

Find the vertex:

 $y=\left(x+3\right)^2-6$  

• (3, 6)

• (x, y)

• (-3, -6)

• (3, -6)

Answer explanation

When finding the vertex in vertex form, your equation is written  $y=a\left(x-h\right)^2+k$  , and your vertex is (h, k). But remember, you want the OPPOSITE of h in your equation.

If you have  $y=\left(x+3\right)^2-6$  , then h = -3 and k = -6 making your vertex (-3, -6)

Find the vertex:

 $y=\left(x+5\right)^2+8$  

• (5, -8)

• (-5, 8)

• (-5, -8)

• (5, 8)

Answer explanation

When finding the vertex in vertex form, your equation is written  $y=a\left(x-h\right)^2+k$  , and your vertex is (h, k). But remember, you want the OPPOSITE of h in your equation.If you have  $y=\left(x+3\right)^2-6$  , then h = -3 and k = -6 making your vertex (-3, -6)

Find the vertex:

 $y=-\left(x-2\right)+15$  

• -(-2, 15)

• (2, -15)

• (15, 2)

• (2, 15)

Answer explanation

When finding the vertex in vertex form, your equation is written  $y=a\left(x-h\right)^2+k$  , and your vertex is (h, k). But remember, you want the OPPOSITE of h in your equation.If you have  $y=\left(x+3\right)^2-6$  , then h = -3 and k = -6 making your vertex (-3, -6)

Find the vertex:

 $y=\left(x-7\right)+7$  

• (7, 7)

• (-7, 7)

• can't use the same number

• - (-7, -7)

Answer explanation

When finding the vertex in vertex form, your equation is written  $y=a\left(x-h\right)^2+k$  , and your vertex is (h, k). But remember, you want the OPPOSITE of h in your equation.If you have  $y=\left(x+3\right)^2-6$  , then h = -3 and k = -6 making your vertex (-3, -6)

Find the vertex:

 $y=2\left(x-5\right)+3$  

• 2(-5, 3)

• (5, -3)

• (10, 6)

• (5, 3)

Answer explanation

When finding the vertex in vertex form, your equation is written  $y=a\left(x-h\right)^2+k$  , and your vertex is (h, k). But remember, you want the OPPOSITE of h in your equation.If you have  $y=\left(x+3\right)^2-6$  , then h = -3 and k = -6 making your vertex (-3, -6)