Creating/Solving Equations

• A
• B
• C
• D

Tags

CCSS.6.EE.A.2A

When 18 is subtracted from six times a certain number, the result -42. What is the equation and number?

• $18-6x=-42$ $x=10$

• 
  

  $6x-18=-42$ $x=-4$
  

• $6x-18=42$ $x=10$

• $18-6x=42$ $x=4$

A certain number added twice to itself equals 96. What is the equations and the number?

• $2\left(x+x+x\right)=96$ $x=16$

• $x+x=96$ $x=48$

• $x+x+x=96$ $x=32$

The sum of three consecutive integers is 48.  What is the smallest number in the group?

• 16
• 15
• 17
• 24

Tags

CCSS.8.EE.C.7B

Which of the following setups would be used to find four consecutive integers?

• n
  n+2
  n+4
  n+6
• n
  2n
  4n
  6n
• n+1
  n+2
  n+3
  n+4
• n
  n+1
  n+2
  n+3

Tags

CCSS.HSA.CED.A.1

Which expressions can be used to represent the sum of 3 consecutive odd integers?

• n+1, n+2, n+3
• n, n+1, n+3
• n, n+1, n+2
• n, n+2, n+4

Tags

CCSS.6.EE.B.6

Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70. What is the equations and integers?

• $x+2\left(x+2\right)+3\left(x+4\right)=70$ $9,\ 11,\ 13$

• $x+x+2+x+4=70$ $9,\ 11,\ 13$

• $x+2\left(x+1\right)+3\left(x+2\right)=70$ $9,\ 11,\ 13$

The second angle of a triangle is the same size as the first angle. The third angle is 12 degrees larger than the first angle. Write an equation that represents the problem.

• $x+x+x+12=180$

• $x+x+x+12=360$

• $x+x+12=180$

• $x+x+12=360$

The second angle of a triangle is five times as large as the first. The measure of the third angle is 12 degrees greater than that of the first angle. Create an equation that matches the situation and find the 3 angles.

• $5+x+x+12+x=180$

• $18,\ 23,\ 30$

• $5x+x+12+x=180$

• $32,\ 96,\ 52$

The perimeter of a rectangle is 150 cm. The length is 15cm greater than the width. Create an equation and find the dimensions. (Hint: you should mark 2 answers)

• $2x+2\left(x+15\right)=150$

• $x+2\left(x+15\right)=150$

• w = 30cm l = 45cm

• $w=\frac{135}{2}cm\ \ \ \ \ \ \ l=\frac{165}{2}cm$