Exponential & Logarithmic Test PART 1

Rewrite the equation in logarithmic form:

 $11^x=128$  

•  $\log_{11}128=x$  

•  $\log_{128}x=11$  

•  $\log_{11}x=128$  

•  $\log_x11=128$  

Rewrite the equation in exponential form:

 $\log_9x=y$  

•  $x^y=9$  

•  $y^x=9$  

•  $x^9=y$  

•  $9^y=x$  

Evaluate the expression:

 $\log_4\ \frac{1}{16}\ =\ ?$  

 $\log_7\ 24=\ ?$  

Approximate the value to the nearest thousandth:

 $\ \ Expand.\ \ \ \log_9\left(\frac{8^2}{5}\right)$   

•  $\log_97\ +\ \frac{\log_98}{2}\ +\ \frac{\log_95}{2}$  

•  $\log_98^{2\ }+\ \log_95$  

•  $2\log_98^{\ }-\ 5\ \log_92$  

•  $2\log_98-\log_95$  

 $5\ \log_2a-4\ \log_2b$  

Condense the expression to a single logarithm:

•  $\log_2\left(b^4a^5\right)$  

•  $\log_2\sqrt{ba}$  

•  $\log_2\left(\frac{a^5}{b^4}\right)$  

•  $\log_25a-\log_24b$  

 $-2\cdot8^{-4x}+1=-90$  

Solve the equation. Round your answer to the nearest ten-thousandth.

• -0.9742

• -0.9544

• -0.4145

• -0.4590

 $\log_33x-\log_37=1$  

Solve the equation.

•  $\frac{189}{5}$  

•  $7$  

•  $-\frac{23}{12}$  

•  $\frac{79}{10}$  

Solve the equation.

 $2\ \log\left(-7k\right)=6$  

•  $\frac{4}{3}$  

•  $730$  

•  $-\frac{343}{6}$  

•  $-\frac{1000}{7}$  

You invest $5,000. in an account that pays 3.5% interest compounded continuously. Find the account balance after 7 years.