12.1 Triangle Proportionality Theorem

Find the missing length indicated.

• 30
• 25
• 45
• 50

Tags

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

CCSS.HSG.SRT.B.4

CCSS.HSG.SRT.B.5

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Solve for x

• 23.1
• 47.1
• 8.5
• 25

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.11

Solve for x.

• 18

• 12

• 6.75

• 85.3

Tags

CCSS.7.EE.B.4

CCSS.7.G.A.1

CCSS.7.RP.A.2

CCSS.7.RP.A.3

Find the missing length indicated.

• 6

• 10

• 5

• 12

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.11

What can we conclude about MN and KL?

• They are parallel by Triangle Proportionality Theorem

• They are parallel by the Converse of the Triangle Proportionality Theorem

• They are congruent by SSS

• They will intersect 10 units down from N

Tags

CCSS.HSG.CO.C.10

CCSS.HSG.GPE.B.5

Which proportion could be used to prove that  $HJ\parallel KL$  ?

•  $\frac{KL}{HJ}=\frac{KG}{LG}$  

•  $\frac{KH}{KG}=\frac{LG}{LJ}$  

•  $\frac{HK}{JL}=\frac{LG}{GK}$  

•  $\frac{GK}{HK}=\frac{GL}{LJ}$  

Tags

CCSS.HSG.GPE.B.5

CCSS.HSG.SRT.A.2

CCSS.HSG.SRT.A.3

CCSS.HSG.SRT.B.5

Are the segments that appear to be parallel actually parallel?

• YES!

• NO!

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.9

CCSS.HSG.GPE.B.5

Find the value of x.

• 10
• 35
• 8
• None of these

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSA.SSE.A.1

What is the measure of x?

• 12
• 15
• 6
• 9

Tags

CCSS.HSG.CO.C.9

Solve for x

• 16
• 1.9
• 19
• 35

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3