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Funcții trigonometrice inverse

Authored by Cristina Bornea

Mathematics

10th Grade

Used 3+ times

Funcții trigonometrice inverse
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8 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Sa se calculeze valoarea expresiei:

 arcsin 817+arcsin 1517\arcsin\ \frac{8}{17}+\arcsin\ \frac{15}{17}  

 π\pi  

 π6\frac{\pi}{6}  

 π2\frac{\pi}{2}  

 π4\frac{\pi}{4}  

 π3\frac{\pi}{3}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Numarul

 m=tg(arctg 12+arctg 13)m=tg\left(ar\operatorname{ctg}\ \frac{1}{2}+ar\operatorname{ctg}\ \frac{1}{3}\right)  are valoarea:

 m=1m=-1  

 m=0m=0  

 m=1m=1  

 m=3m=\sqrt{3}  

 m=13m=\frac{1}{\sqrt{3}}  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Sa se rezolve ecuatia :

 arcsin(1x)=arccos(1+x)\arcsin\left(1-x\right)=\arccos\left(1+x\right)  

 x=0x=0  

 x=12x=\frac{1}{2}  

 x{0,12}x\in\left\{0,\frac{1}{2}\right\}  

 x[1,0]x\in\left[-1,0\right]  

ecuatia nu are nici o solutie

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie

 α=arcsin(sin(3π4))\alpha=\arcsin\left(\sin\left(-\frac{3\pi}{4}\right)\right)  . Atunci:

 α=3π4\alpha=\frac{3\pi}{4}  

 α=3π4\alpha=-\frac{3\pi}{4}  

 α=π4\alpha=-\frac{\pi}{4}  

 α=π4\alpha=\frac{\pi}{4}  

 α=0\alpha=0  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Sa se calculeze valoarea expresiei:

 E=arccos 13arctg22E=\arccos\ \frac{1}{3}-ar\operatorname{ctg}2\sqrt{2}  

-1

0

 12-\frac{1}{2}  

 arctg 12ar\operatorname{ctg}\ \frac{1}{2}  

1

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie

 E=sin(arccos 35+arccos 1517)E=\sin\left(\arccos\ \frac{3}{5}+\arccos\ \frac{15}{17}\right)  .Atunci:

 E=3435E=\frac{34}{35}  

 E= 8485E=\ \frac{84}{85}  

 E=8385E=\frac{83}{85}  

 E=1385E=\frac{13}{85}  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Suma

 S=arcsina+arccosa+arctga+arcctgaS=\arcsin a+\arccos a+ar\operatorname{ctg}a+\operatorname{arcctg}a  este data de:

 S=0S=0  

 S=π2S=\frac{\pi}{2}  

 S=πS=\pi  

 S=π2S=-\frac{\pi}{2}  

 S=πS=-\pi  

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