Alg 2 HW Jan 23

Evaluate the following logarithm:

log₃27

• 3

• 2

• -3

• ¹/₃

Tags

CCSS.HSF.BF.B.5

Evaluate the following logarithm:

log₃(¹/₃)

• -2

• -¹/₂

• -1

• ¹/₂

Tags

CCSS.HSF.BF.B.5

Write log_b(xy) as two logs

• log_bx+log_by
• log_bx-log_by
• log_bx*log_by
• log_bx/log_by

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Write log_b(x/y) as two logs

• log_bx-log_by
• log_bx+log_by
• log_bx*log_by
• log_bx/log_by

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Rewrite log₂8 = 3 in exponential form

• 2⁸ = 3

• 2³ = 8

• 3² = 8

• 8³ = 2

Tags

CCSS.HSF.BF.B.5

Write in logarithmic form

2^-4 = ¹/₁₆

• log₂(¹/₁₆) = -4

• log_-4(¹/₁₆) = 2

• log _-4 2 = ¹/₁₆

• log₂(-4) = ¹/₁₆

Tags

CCSS.HSF.BF.B.5

Write as one logarithm. Simplify, if possible.
log₂800 - log₂100

• 8
• 3
• -3
• 1

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

Write as one logarithm. Simplify, if possible.
log₅125 - log₅25

• 1
• 0
• 5
• -1

Tags

CCSS.HSF.BF.B.5

Write in logarithmic form.
2^-4 = ¹/₁₆

• log₂(¹/₁₆) = -4
• log_-4(¹/₁₆) = 2
• log _-4 2 = ¹/₁₆
• log₂(-4) = ¹/₁₆

Tags

CCSS.HSF.BF.B.5

Rewrite log_b(xⁿ)

• nlog_bx
• (log_bx)ⁿ
• xⁿlog_bx
• log_b(xⁿ)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8