Prueba Corta 1 Matemática Aplicada 5to Bach

Prueba Corta 1 Matemática Aplicada 5to Bach

11th Grade

10 Qs

quiz-placeholder

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Prueba Corta 1 Matemática Aplicada 5to Bach

Prueba Corta 1 Matemática Aplicada 5to Bach

Assessment

Quiz

Mathematics

11th Grade

Hard

Created by

Mario Hernandez

Used 2+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Demuestre si el punto se encuentra dentro de la circunferencia unitaria

 P(33, 63)P\left(\frac{\sqrt{3}}{3},\ \frac{\sqrt{6}}{3}\right)  

Verdadero

Falso

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Encuentre la coordenada faltante dada la información

 P (32,   ) en el IV cuadranteP\ \left(\frac{\sqrt{3}}{2},\ \ \ \right)\ en\ el\ IV\ cuadrante  

 12\frac{1}{2}  

 ±12\pm\frac{1}{2}  

 12-\frac{1}{2}  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Indique el punto terminal para el valor dado de t

 t=50π6t=-\frac{50\pi}{6}  

 (12, 32)\left(\frac{1}{2},\ \frac{\sqrt{3}}{2}\right)  

 (32, 12)\left(\frac{\sqrt{3}}{2},\ -\frac{1}{2}\right)  

 (12, 32)\left(\frac{1}{2},\ -\frac{\sqrt{3}}{2}\right)  

 (32, 12)\left(\frac{\sqrt{3}}{2},\ \frac{1}{2}\right)  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Indique el número de referencia del valor dado de t

 t=38π4t=\frac{38\pi}{4}  

 t=2π4\overline{t}=-\frac{2\pi}{4}  

 t=2π4\overline{t}=\frac{2\pi}{4} 

 t=±2π4\overline{t}=\pm\frac{2\pi}{4}  

 t=±π2\overline{t}=\pm\frac{\pi}{2}  

 t=π2\overline{t}=-\frac{\pi}{2}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Encuentre el valor de

 Sen 19π4Sen\ -\frac{19\pi}{4}  

 22\frac{\sqrt{2}}{2}  

 ±22\pm\frac{\sqrt{2}}{2}  

 22-\frac{\sqrt{2}}{2}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Encuentre el valor de

 Cot 15π9Cot\ \frac{15\pi}{9}  

 13-\frac{1}{\sqrt{3}}  

 3-\sqrt{3}  

 13\frac{1}{\sqrt{3}}  

 3\sqrt{3}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Determine el signo de la expresión

 (Cot t Csc t)×(Sen tSec t)tant, en el II Cuadrante\frac{\left(\frac{Cot\ t\ }{Csc\ t}\right)\times\left(\frac{Sen\ t}{Sec\ t}\right)}{\tan t},\ en\ el\ II\ Cuadrante  

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