BUKTI KEHADIRAN 17-18 FEB 2021

To differentiate

 $y=5\left(x^2-8\right)$  , the first step is remove the bracket.

• True

• False

Differentiate

 $y=3\left(x^4-8\right)$ 

•  $\frac{\text{d}y}{\text{d}x}=12x^3$  
  

•  $\frac{\text{d}y}{\text{d}x}=12x^3-24$  

•  $\frac{\text{d}y}{\text{d}x}=3\left(4x^3-0\right)$  

•  $\frac{\text{d}y}{\text{d}x}=3\left(4x^3-8\right)$  

Differentiate

 $y=x^2\left(x+6\right)$ 

•  $\frac{\text{d}y}{\text{d}x}=x^3+6x^2$  
  

•  $\frac{\text{d}y}{\text{d}x}=3x^2+12x$  

•  $\frac{\text{d}y}{\text{d}x}=x^3-6x^2$  

•  $\frac{\text{d}y}{\text{d}x}=3x^2-12x$  

Differentiate

 $y=\left(x+4\right)\left(x+5\right)$ 

•  $\frac{\text{d}y}{\text{d}x}=x^2+9x+20$  
  

•  $\frac{\text{d}y}{\text{d}x}=2x+9$  

•  $\frac{\text{d}y}{\text{d}x}=2x+9x$  

•  $\frac{\text{d}y}{\text{d}x}=2x+9x+20$  

Differentiate

 $y=\left(x+7\right)^2$ 

•  $\frac{\text{d}y}{\text{d}x}=x^2+14x+49$  
  

•  $\frac{\text{d}y}{\text{d}x}=2x+14$  

•  $\frac{\text{d}y}{\text{d}x}=\left(x+7\right)\left(x+7\right)$  

•  $\frac{\text{d}y}{\text{d}x}=2x+14x+49$