Dimensional Analysis Setup Only

What unit should be in the denominator (bottom) of the conversion factor?

• yards

• leagues

• feet

• fathoms

What unit should be in the numerator (top) of the conversion factor?

• yards

• leagues

• feet

• fathoms

What conversion factor would you use to solve this problem?

• 2.20 lbs / 1 kg
• 1 kg / 2.20 lbs
• 0.002 lbs / 1 g
• 1 g / 0.002 lbs

Which conversion factor would be needed?

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Which conversion factor would be needed?

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Which of the following shows the correct work to convert 25.0 inches to cm? (Relationship: 1 inch = 2.54 cm)

•  $25.0\ in\ \ x\ \ \frac{2.54\ cm}{1\ in}=$  

•  $2.54\ cm\ x\ \frac{1\ in}{25.0\ cm}=$  

•  $1\ in\ x\ \frac{2.54\ cm}{25\ in}=$  

•  $25\ in\ x\ \frac{1\ in}{2.54\ cm}=$  

Which of the following choices shows the correct setup to find out how many yards are in 575 inches?

•  $575\ yd\ \ x\ \ \frac{3\ ft}{1\ yd}\ x\ \frac{12\ in}{1\ ft}=$ 

•  $575\ in\ \ x\ \ \frac{1\ ft}{12\ in}\ x\ \frac{1\ yd}{3\ ft}=$ 

•  $575\ in\ \ x\ \ \frac{12\ in}{1\ ft}\ x\ \ \frac{3\ ft}{1\ yd}\ =\$ 

•  $575\ in\ \ x\ \frac{1\ ft}{12\ in}\ x\ \ \frac{3\ ft}{1\ yd}=$ 

If 1 mile = 1.61 km and 1000m = 1km, what is the correct work to solve how many miles are in 9,999 meters?

•  $9,999\ m\ x\ \frac{1.61\ km}{1\ m}\ x\ \frac{1\ mi}{1000\ m}=$  

•  $9,999\ m\ x\ \frac{1\ km}{1000\ m}x\ \frac{1\ mi}{1.61\ km}=$  

•  $1.61\ km\ x\ \frac{1\ mi}{1000\ km}x\ \frac{9999\ m}{1\ mi}=$  

•  $9,999\ m\ x\ \frac{1.61\ km}{1\ mi}\ =\$