
Solving Systems of Equations by the Substitution Method
Authored by Douglas Spivey
Mathematics
8th - 9th Grade
CCSS covered
Used 216+ times

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9 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Quick Review of the Graphing Method:
How many solutions does the graph have?
One solution
No solution
Infinite solutions
Tags
CCSS.8.EE.C.8B
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Quick Review of the Graphing Method:
How many solutions does the graph have?
One solution
No solution
Infinite solutions
Tags
CCSS.8.EE.C.8B
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Quick Review of the Graphing Method:
How many solutions does the graph have?
One solution
No solution
Infinite solutions
Tags
CCSS.8.EE.C.8B
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The first step in solving a system of equations using the SUBSTITUTION METHOD is __________.
(Read all the answers before choosing one.)
get x by itself
get y by itself
get EITHER x or y by itself
add the equations together
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Which answer has a correct next step for this system? (Read all three answers carefully before selecting one!)
y = 6x
2x + 5y = 32
The variable is already isolated, so we've already solved the system.
The variable is already isolated for y, so we substitute it in the second equation like this:
2(6x) + 5y = 32
The variable is already isolated for y, so we substitute it in the second equation like this:
2x + 5(6x) = 32
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Use the system of equations below to answer the question.
After substituting the first equation into the second one and working it out, I got x = 1. What should I do next?
y = 6x
2x + 5y = 32
Fill in 1 for x in y = 6x
Fill in 1 for y in y = 6x
Fill in 1 for y in 2x + 5y = 32
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Which answer has a correct next step for this system? (Read all three answers carefully before selecting one!)
3x + 4y = 3
y = 3x + 5
The variable is already isolated, so we've already solved the system.
The variable is already isolated for y, so we substitute 3x + 5 in the first equation like this:
3x + 4(3x + 5) = 3
The variable is already isolated for y, so we substitute 3x + 5 in the second equation like this:
3(3x + 5) + 4y = 3
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
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