sin ⁡ ( ∠ ) = \sin\left(\angle\right)= sin ( ∠ ) =

o p p o s i t e h y p o t e n u s e \frac{opposite}{hypotenuse} h y p o t e n u s e o p p o s i t e

a d j a c e n t h y p o t e n u s e \frac{adjacent}{hypotenuse} h y p o t e n u s e a d j a c e n t

o p p o s i t e a d j a c e n t \frac{opposite}{adjacent} a d j a c e n t o p p o s i t e

cos ⁡ ( ∠ ) = \cos\left(\angle\right)= cos ( ∠ ) =

a d j a c e n t h y p o t e n u s e \frac{adjacent}{hypotenuse} h y p o t e n u s e a d j a c e n t

o p p o s i t e h y p o t e n u s e \frac{opposite}{hypotenuse} h y p o t e n u s e o p p o s i t e

o p p o s i t e a d j a c e n t \frac{opposite}{adjacent} a d j a c e n t o p p o s i t e

tan ⁡ ( ∠ ) = \tan\left(\angle\right)= tan ( ∠ ) =

o p p o s i t e a d j a c e n t \frac{opposite}{adjacent} a d j a c e n t o p p o s i t e

o p p o s i t e h y p o t e n u s e \frac{opposite}{hypotenuse} h y p o t e n u s e o p p o s i t e

a d j a c e n t h y p o t e n u s e \frac{adjacent}{hypotenuse} h y p o t e n u s e a d j a c e n t

sin ⁡ ( A ) = \sin\left(A\right)= sin ( A ) = Simplify and rationalize all ratios!

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ ( A ) = \cos\left(A\right)= cos ( A ) = Simplify and rationalize all ratios!

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

tan ⁡ ( A ) = \tan\left(A\right)= tan ( A ) = Simplify and rationalize all ratios!

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

sin ⁡ ( B ) = \sin\left(B\right)= sin ( B ) = Simplify and rationalize all ratios!

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ ( B ) = \cos\left(B\right)= cos ( B ) = Simplify and rationalize all ratios!

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

tan ⁡ ( B ) = \tan\left(B\right)= tan ( B ) = Simplify and rationalize all ratios!

2 5 5 \frac{2\sqrt{5}}{5} 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 \frac{\sqrt{5}}{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

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Trig Ratios

Quiz

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Mathematics

•

10th Grade

•

Practice Problem

•

Medium

•

CCSS

HSG.SRT.C.6, HSG.SRT.C.8, HSG.SRT.D.11

Standards-aligned

Taylor Torre

Used 323+ times

FREE Resource

20 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side is OPPOSITE of $\angle A$ ?

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side is OPPOSITE of $\angle B$ ?

Tags

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side is ADJACENT to $\angle A$ ?

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which side is ADJACENT to $\angle B$ ?

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\left(\angle\right)=$

$\frac{opposite}{hypotenuse}$

$\frac{adjacent}{hypotenuse}$

$\frac{opposite}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\left(\angle\right)=$

$\frac{opposite}{hypotenuse}$

$\frac{adjacent}{hypotenuse}$

$\frac{opposite}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\tan\left(\angle\right)=$

$\frac{opposite}{hypotenuse}$

$\frac{adjacent}{hypotenuse}$

$\frac{opposite}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\left(R\right)=$
Simplify all ratios!

$\frac{28}{53}$

$\frac{45}{53}$

$\frac{45}{28}$

$\frac{28}{45}$

Answer explanation

opposite/hypotenuse

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\left(R\right)=$
Simplify all ratios!

$\frac{28}{53}$

$\frac{45}{53}$

$\frac{45}{28}$

$\frac{28}{45}$

Answer explanation

adjacent/hypotenuse

Tags

CCSS.HSG.SRT.C.6

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\tan\left(R\right)=$
Simplify all ratios!

$\frac{28}{53}$

$\frac{45}{53}$

$\frac{45}{28}$

$\frac{28}{45}$

Answer explanation

opposite/adjacent

Tags

CCSS.HSG.SRT.C.6

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Trig Ratios

20 questions

Which side is OPPOSITE of ∠A\angle A∠A ?

Which side is OPPOSITE of ∠B\angle B∠B ?

Which side is ADJACENT to ∠A\angle A∠A ?

Which side is ADJACENT to ∠B\angle B∠B ?

sin⁡(∠)=\sin\left(\angle\right)=sin(∠)=

cos⁡(∠)=\cos\left(\angle\right)=cos(∠)=

tan⁡(∠)=\tan\left(\angle\right)=tan(∠)=

sin⁡(R)=\sin\left(R\right)=sin(R)= Simplify all ratios!

opposite/hypotenuse

cos⁡(R)=\cos\left(R\right)=cos(R)= Simplify all ratios!

adjacent/hypotenuse

tan⁡(R)=\tan\left(R\right)=tan(R)= Simplify all ratios!

opposite/adjacent

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Which side is OPPOSITE of $\angle A$ ?

Which side is OPPOSITE of $\angle B$ ?

Which side is ADJACENT to $\angle A$ ?

Which side is ADJACENT to $\angle B$ ?

$\sin\left(\angle\right)=$

$\cos\left(\angle\right)=$

$\tan\left(\angle\right)=$

$\sin\left(R\right)=$
Simplify all ratios!

$\cos\left(R\right)=$
Simplify all ratios!

$\tan\left(R\right)=$
Simplify all ratios!