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Separation of variables

Authored by Venkata Rachakulla

Mathematics

12th Grade

Used 24+ times

Separation of variables
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17 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The differential equation  dy dx=xy+2y\frac{\ dy\ }{dx}=xy+2y  written correctly in separable form is 

 dyy+2y=xdx\frac{dy}{y+2y}=xdx  

 ydyy=2xdxydy-y=2xdx  

 dyy=(x+2)dx\frac{dy}{y}=\left(x+2\right)dx  

 (y2)dy=xdx\left(y-2\right)dy=xdx  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A function  y=f(x)y=f\left(x\right) that satisfies the equation  ydydx=xy\frac{\text{d}y}{\text{d}x}=x  and  f(0)=1f\left(0\right)=1  is  

 f(x)=xf\left(x\right)=x  

 f(x)=exf\left(x\right)=e^x  

 f(x)=x2+1f\left(x\right)=\sqrt{x^2+1}  

 f(x)=1x2f\left(x\right)=\sqrt{1-x^2}  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 dxdy4y5+e2x=0\frac{\text{d}x}{\text{d}y}-4y-5+e^{-2x}=0  

The general solution for the above DE is,

 y=20+6e2x+Ce4xy=-20+6e^{-2x}+Ce^{4x}  

 y=54e4x+16e2x+Ce4xy=-\frac{5}{4}e^{-4x}+\frac{1}{6}e^{-2x}+Ce^{4x}  

 y=20e8x+e10x+Ce4xy=-20e^{-8x}+e^{-10x}+Ce^{-4x}  

 y=54+16e2x+Ce4xy=-\frac{5}{4}+\frac{1}{6}e^{-2x}+Ce^{-4x}  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following mathematical models CANNOT be solved by using separation of variables

dPdt=kP\frac{\text{d}P}{\text{dt}}=kP

dTdt=k(TTm)\frac{dT}{dt}=k\left(T-Tm\right)

dAdt=kA\frac{dA}{dt}=kA

L dIdt+RI=E(t)L\ \frac{dI}{dt}+RI=E\left(t\right)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

By separation of variables, solve the resulting equations  vv+1dv= 1ydy\int\ \frac{v}{v+1}dv=\int_{ }^{ }\ \frac{1}{y}dy\text{}  

 xylnxy+1=lny+C\frac{x}{y}-\ln\left|\frac{x}{y}+1\right|=\ln y+C  

 xy+lnxy+1=lny+C\frac{x}{y}+\ln\left|\frac{x}{y}+1\right|=\ln y+C  

 xy+x22y2=lny+C\frac{x}{y}+\frac{x^2}{2y^2}=\ln y+C  

 xyx22y2=lny+C\frac{x}{y}-\frac{x^2}{2y^2}=\ln y+C  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 Solve the given differential equations by separable variable method   dvdt=3+v2v\frac{\text{d}v}{\text{d}t}=\frac{3+v^2}{v}  

 v=ln3+v2+Cv=\ln\left|3+v^2\right|+C  

 v2=e2t+2c3v^2=e^{2t+2c}-3  

 v=Ae2t+3,     A=e2cv=Ae^{2t}+3,\ \ \ \ \ A=e^{2c}  

 v2=Ae2t+3,      A=Cv^2=Ae^{2t}+3,\ \ \ \ \ \ A=C  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 Solve the given differential equations by separable variable method   dydx=ey(2x4),     y(5)=0\frac{\text{d}y}{\text{d}x}=e^{-y}\left(2x-4\right),\ \ \ \ \ y\left(5\right)=0  

 y=lnx24x4y=\ln\left|x^2-4x-4\right|  

 y=x24x4y=x^2-4x-4  

 y=4e2t+4     A=e2cy=4e^{2t}+4\ \ \ \ \ A=e^{2c}  

 y2=4e2x+2,      A=Cy^2=4e^{2x}+2,\ \ \ \ \ \ A=C  

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